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Basiclly, we look at the 2 points below and find the distance between them, then we match
d=
when finding the distance between points (x1,y1) and (x2,y2)
if the x values, or y values are same, you don't need the distance formula, just use logic
(-10, 2) and (-2, 2)
the y value is the same so find the distance between the x values
from -10 to -2 is 8
8 matches with this one
(-3, -1) and (5, 1)
use distance formula
d=
=√68
(-3, -2) and (1, 3)
input
d=
=√41
(-3, -5) and (-2, -4)
input
d=
=√2
(0, 0) and (5, 5)
input
d=
=√50
(1, 2) and (1, -10)
x values are same so find distance between 2 and -10
answer is 12
(1, 2) and (5, 2)
y values are same
find distance between 1 and 5
answe ris 4
(2, 3) and (10, 9)
input
d=
=10
ANSWERS (because the spacing has gone wierd)
(-10, 2) and (-2, 2)=8
(-3, -1) and (5, 1)=√68
(-3, -2) and (1, 3)=√41
(-3, -5) and (-2, -4)=√2
(0, 0) and (5, 5)=√50
(1, 2) and (1, -10)=12
(1, 2) and (5, 2)=4
(2, 3) and (10, 9)=10
d=
when finding the distance between points (x1,y1) and (x2,y2)
if the x values, or y values are same, you don't need the distance formula, just use logic
(-10, 2) and (-2, 2)
the y value is the same so find the distance between the x values
from -10 to -2 is 8
8 matches with this one
(-3, -1) and (5, 1)
use distance formula
d=
(-3, -2) and (1, 3)
input
d=
(-3, -5) and (-2, -4)
input
d=
(0, 0) and (5, 5)
input
d=
(1, 2) and (1, -10)
x values are same so find distance between 2 and -10
answer is 12
(1, 2) and (5, 2)
y values are same
find distance between 1 and 5
answe ris 4
(2, 3) and (10, 9)
input
d=
ANSWERS (because the spacing has gone wierd)
(-10, 2) and (-2, 2)=8
(-3, -1) and (5, 1)=√68
(-3, -2) and (1, 3)=√41
(-3, -5) and (-2, -4)=√2
(0, 0) and (5, 5)=√50
(1, 2) and (1, -10)=12
(1, 2) and (5, 2)=4
(2, 3) and (10, 9)=10
x = -3 → -3 = -3 and -3 < 4 therefore -3 ≤ -3 ≤ 4
x = -2.2 → -3 < -2.2 and -2.2 < 4 therefore -3 ≤ -2.2 ≤ 4
x = -2 → -3 < -2 and -2 < 4 therefore -3 ≤ -2 ≤ 4
x = 0 → -3 < 0 and 0 < 4 therefore -3 ≤ 0 ≤ 4
x = 1.5 → -3 < 1.5 and 1.5 < 4 therefore -3 ≤ 1.5 ≤ 4
x = 3 → -3 < 3 and 3 < 4 th≤erefore -3 ≤ 3 ≤ 4
x = 4 → -3 < 4 and 4 = 4 therefore -3 ≤ 4 ≤ 4