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topjm [15]
3 years ago
6

A vector is used to express a car's change in position, or displacement, by tracking its motion over a large area defined by a c

oordinate grid. If the car begins at (−3,−5) and ends at (5,9), which of these expresses the car's displacement in vector form?
A
(14,8)

B
(10,12)

C
(8,14)

D
(2,4)
Mathematics
2 answers:
kirill [66]3 years ago
8 0

Answer:

C(8,14)

Step-by-step explanation:

initial point (-3,-5) and terminal point (5,9)

vector form=(change in x, change in y)

V=(Xf-Xi,Yf-Yi)

V=[5-(-3), 9-(-5)]

V=(8,14)

GaryK [48]3 years ago
6 0
The answer is C. Hope this helps
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Joaquin bought a bookcase on sale for $120, which was two-thirds of the original price. What was the original price of the bookc
weqwewe [10]
180
Because 120 divided by 2 is 60.
And 120 + 60 is 180
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3 years ago
Please help! how do i know if it’s sin, cos, or tan if they’ve already given me all three numbers ?
zysi [14]

Answer:

Here you can use any!

sin x = 64/80

cos x = 48/80

tan x = 64/48

5 0
2 years ago
Urgent help please !!!
chubhunter [2.5K]

Answer:

The answer is A. 3x + 3

Step-by-step explanation:

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6 0
2 years ago
Solve (x – 3)2 = 49. Select the values of x. –46 -4 10 52
sergiy2304 [10]

After using the algebraic equation, the required value of x = 55/2.

WHAT IS ALGEBRIC EQUATION?
A mathematical statement wherein two expressions have been set equal to one another is known as an algebraic equation. A variable, coefficients, and constants make up an algebraic equation in most cases. Equations, or the equal sign, simply indicate equality. Equating each quantity with another is what equations are all about. Equations act as a scale of balance. If you've ever seen a balance scale, users know that for the scale to be deemed "balanced," an equal amount of weight must be applied to each side. The scale will tip to one side if we only add weight to one side, and the two sides will no longer be equally weighted.

(x-3)2 = 49

= x-3 = 49/2

= x = (49/2) + 3

= x = 55/2

So, the required value of x = 55/2.

To know more about algebraic equation click on the below given link

brainly.com/question/24875240

#SPJ1

4 0
11 months ago
Let the number of chocolate chips in a certain type of cookie have a Poisson distribution. We want the probability that a cookie
ludmilkaskok [199]

Answer:

\lambda \geq 6.63835

Step-by-step explanation:

The Poisson Distribution is "a discrete probability distribution that expresses the probability of a given number of events occurring in a fixed interval of time or space if these events occur with a known constant mean rate and independently of the time since the last event".

Let X the random variable that represent the number of chocolate chips in a certain type of cookie. We know that X \sim Poisson(\lambda)

The probability mass function for the random variable is given by:

f(x)=\frac{e^{-\lambda} \lambda^x}{x!} , x=0,1,2,3,4,...

And f(x)=0 for other case.

For this distribution the expected value is the same parameter \lambda

E(X)=\mu =\lambda

On this case we are interested on the probability of having at least two chocolate chips, and using the complement rule we have this:

P(X\geq 2)=1-P(X

Using the pmf we can find the individual probabilities like this:

P(X=0)=\frac{e^{-\lambda} \lambda^0}{0!}=e^{-\lambda}

P(X=1)=\frac{e^{-\lambda} \lambda^1}{1!}=\lambda e^{-\lambda}

And replacing we have this:

P(X\geq 2)=1-[P(X=0)+P(X=1)]=1-[e^{-\lambda} +\lambda e^{-\lambda}[]

P(X\geq 2)=1-e^{-\lambda}(1+\lambda)

And we want this probability that at least of 99%, so we can set upt the following inequality:

P(X\geq 2)=1-e^{-\lambda}(1+\lambda)\geq 0.99

And now we can solve for \lambda

0.01 \geq e^{-\lambda}(1+\lambda)

Applying natural log on both sides we have:

ln(0.01) \geq ln(e^{-\lambda}+ln(1+\lambda)

ln(0.01) \geq -\lambda+ln(1+\lambda)

\lambda-ln(1+\lambda)+ln(0.01) \geq 0

Thats a no linear equation but if we use a numerical method like the Newthon raphson Method or the Jacobi method we find a good point of estimate for the solution.

Using the Newthon Raphson method, we apply this formula:

x_{n+1}=x_n -\frac{f(x_n)}{f'(x_n)}

Where :

f(x_n)=\lambda -ln(1+\lambda)+ln(0.01)

f'(x_n)=1-\frac{1}{1+\lambda}

Iterating as shown on the figure attached we find a final solution given by:

\lambda \geq 6.63835

4 0
2 years ago
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