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3 years ago

11

I need to know where to put the lines

2 answers:

IrinaK [193]3 years ago

8 0

Answer:

put them on the points

Step-by-step explanation:

scZoUnD [109]3 years ago

6 0

The easiest way to say this is to draw the point with its correct quadrant

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Solve for x:<br> 27^(2x)=(1/9)^(x-3)

elena-14-01-66 [18.8K]

$27^{2x}=\left(\dfrac{1}{9}\right)^{x-3}\\\\(3^3)^{2x}=\left(\dfrac{1}{3^2}\right)^{x-3}\\\\3^{3\cdot2x}=(3^{-2})^{x-3}\\\\3^{6x}=3^{-2(x-3)}\\\\3^{6x}=3^{-2x+6}\iff6x=-2x+6\ \ \ |add\ 2x\ to\ both\ sides\\\\8x=6\ \ \ |divide\ both\ sides\ by\ 8\\\\x=\dfrac{6}{8}\\\\\boxed{x=\frac{3}{4}}$

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Yuri [45]

Step-by-step explanation:

I don't see any of the choices, but I'll just give you what it's equal to. The expression is equal to: sqrt2, which is approximately 1.414.

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zhuklara [117]

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Step-by-step explanation:

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3 years ago

7 (f- 1 )=45 solve equation

Karo-lina-s [1.5K]

7(f-1)=45

7xf=7f

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drek231 [11]

Answer:

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