Answer:
H0 : μd = 0
H1 : μd ≠ 0
Test statistic = 0.6687 ;
Pvalue = 0.7482 ;
Fail to reject H0.
Step-by-step explanation:
H0 : μd = 0
H1 : μd ≠ 0
Given the data:
Before: 15 26 66 115 62 64
After: 16 24 42 80 78 73
Difference = -1 2 24 35 -18 -9
Mean difference, d ; Σd / n
d = Σx / n = ((-1) + 2 + 24 + 35 + (-18) + (-9))
d = Σx / n = 33 / 6 = 5.5
Test statistic = (d / std / sqrt(n))
std = sample standard deviation = 20.146
Test statistic = 5.5 ÷ (20.146/sqrt(6))
Test statistic = 0.6687
The Pvalue :
P(Z < 0.6687) = 0.7482
At α = 0.05
Pvalue > α ; Hence we fail to reject H0
The data does not suggest a significant mean difference in the average number of accidents after information was added to road signs.
The answer is independent
ANSWER: 7n-2
m-6n-3/m-13n-1
First you cross cancel m
then you get -6n-3/-13n-1
Thn you would subtract : 7n-2
Answer:
c = 5
Step-by-step explanation:
We can find a, b, c by filling in values from the table into the equation:
17 = a(2²) +b(2) +c
32 = a(3²) +b(3) +c
53 = a(4²) +b(4) +c
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There are numerous ways to solve 3 linear equations in 3 unknowns. We can use elimination.
Subtracting the first equation from each of the other two, we get ...
15 = 5a +b . . . . . . . . . note that c has been eliminated from the equations
36 = 12a +2b
Subtracting twice the first from the second gives ...
(12a +2b) -2(5a +b) = 36 -2(15)
2a = 6
a = 3
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Now that we have a value for "a", we can "back substitute" into the equations to find "b" and "c".
Substituting this into 15 = ..., we get ...
15 = 5(3) +b
0 = b
And substituting for "a" and "b" in the first original equation gives ...
17 = 4(3) +c
5 = c
The value of c, the constant of the function, is 5.
Answer:
what is the particular question?
