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wariber [46]
3 years ago
11

(20 PTS) WILL GIVE BRAINLIST

Mathematics
1 answer:
tatyana61 [14]3 years ago
5 0

Answer:

-6

4

9

19

29

Step-by-step explanation

Plug the numbers into the x.

5(-2)+4

5(0)+4

5(1)+4

5(3)+4

5(5)+4

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A dealer marks a T-shirt with a price 20 PERCENT more than the cost price. It he sells it at a discount of I5 PERCENT.. What wil
Vlada [557]

Answer:

Rs 2,or 2%profit

Step-by-step explanation:

the price he marked:

100 \times  \frac{120}{100}  = 120

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120 \times  \frac{85}{100}

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Brainliest please

6 0
3 years ago
Lizzie rolls two dice. What is the probability that the sum of the dice is:
zhenek [66]

Answer:

A.\ \dfrac{1}{3}\\B.\ \dfrac{5}{12}\\C.\ \dfrac{7}{36}\\

Step-by-step explanation:

Total outcomes possible: 36

A. Divisible by 3

Possible options are:

3, 6, 9 and 12.

Possible outcomes for 3 are: {(1,2), (2,1)} Count 2

Possible outcomes for 6 are: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

Possible outcomes for 9 are: {(3,6), (4,5), (5,4),(6,3)} Count 4

Possible outcomes for 12 are: {(6,6)} Count 1

Total count = 2 + 5 + 4 + 1 = 12

Probability of an event E can be formulated as:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

P(A)  = \dfrac{12}{36} = \dfrac{1}{3}

B. Less than 7:

Possible sum can be 2, 3, 4, 5, 6

Possible cases for sum 2: {(1,1)}  Count 1

Possible cases for sum 3: {(1,2), (2,1)}  Count 2

Possible cases for sum 4: {(1,3), (3,1), (2,2)}  Count 3

Possible cases for sum 5: {(1,4), (2,3), (3,2),(4,1)}  Count 4

Possible cases for sum 6: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

Total count = 1 + 2 + 3 + 4 + 5 = 15

P(B)  = \dfrac{15}{36} = \dfrac{5}{12}

C. Divisible by 3 and less than 7:

P(A \cap B) = \dfrac{n(A\cap B)}{\text{Total Possible outcomes}}

Here, common cases are:

Possible outcomes for 3 are: {(1,2), (2,1)} Count 2

Possible outcomes for 6 are: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

P(A \cap B) = \dfrac{7}{\text{36}}

5 0
3 years ago
In baseball, a player's batting average is calculated by dividing the number of hits by the numbers of at-bats. If player A's ba
Anna11 [10]
Average = no of hits / no of at-bats
0.296 = x / 446
0.296/ 446 = x
132.016
No of hits ≈ 132
8 0
3 years ago
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