I would select A because cells have to divide into smaller cells depending on where they are.
During Telophase 2, a nuclear envelope forms around each set of new chromosomes. In this stage, cytokinesis occurs, which is responsible for producing four daughter cells each with a haploid set of chromosomes. During the crossing-over phase some chromosomes are observed to have segments that have recombined with the original parent chromosomes.
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When the phase is over, the two cells are now finally separated and their nuclear membranes are fully formed causing the meiosis cell division to be completed.</span>
It is D.) because it would sit there forever to who knows. There is always something that is used from something according to the food chain. Take a dead bird for example. Consumers would not want to eat a bird that has no nutrients that is alive. So this is when decomposers swoop in. Maggots, fungi, worms etc. decompose the dead body and if is was fungi, the nutrient will go into the soil and the process starts again providing nutrients to plants.
there is growing evidence that mitochondrial complexes i, ii, iii, and iv are part of a larger supercomplex. the advantage of having all four complexes within a supercomplex is that it makes the electron transport across various complexes easier and faster.
Mitchondria have four types of complexes-
Complex I- NADH/ ubiquinone oxireductase, blue
Complex II- Succinate dehydrogenase, pink
Complex III- Cytochrome c reductase
Complex IV- Cytochrome c oxidase
The electron flows through the various complexes in process of formation of the ATP molecules.
The advantage of having a supercomplex which accomodates all the four types of complexes is that the electron will then flow in solid state which is kinetically more favorable.
To learn more about Mitochondrial Complex here
brainly.com/question/15318900
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