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zysi [14]
2 years ago
12

Find the area of the figure.

Mathematics
1 answer:
valkas [14]2 years ago
8 0

Answer:

37.5 Units

Step-by-step explanation:

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Which linear inequality is represented by the graph?​
zalisa [80]

Answer:

y ≥ \frac{1}{3}x - 1

Step-by-step explanation:

First, determine the slope of the line. We can see that the slope is \frac{1}{3}, because the slope has less than 1 y interval per every x interval. This means that the line is less steep. There are only 2 slope choices, \frac{1}{3}, -\frac{1}{3}\\, and 3. We can tell that the slope is positive, but it must be \frac{1}{3}\\ because it is clearly less steep than a 3 slope line.

Now, look at the portion that is shaded. It is above the line, and this means that y is greater than the equation given. We can tell it is greater than or equal to, because the line that represents the equation is shaded as well. If it was only greater than and not equal to, the line would not be shaded.

Hope this helps ! :) Please feel free to ask me any questions!

7 0
3 years ago
Sam has softball practice every 3 days and drama lessons every 7 days. On what day will both occur?
sweet [91]

Answer:

the 21st day

Step-by-step explanation:

21 is 3 and 7's least common multiple

5 0
3 years ago
Read 2 more answers
What is x in this problem
o-na [289]

Answer:

total \: angle \: for \: a \: triangle = 180 \\ then \:  \\ 3x + 11 + 9x - 16 + 7x - 5 = 180 \\ 19x - 10 = 180 \\ 19x = 180 + 10 \\ 19x = 190 \\ x =  \frac{190}{19}  = 10 \\ thank \: yo

6 0
2 years ago
Read 2 more answers
What is 5 times a number ,r, decreased by seven
Lapatulllka [165]

Answer:

5n - 7 < 23

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Give a 98% confidence interval for one population mean, given asample of 28 data points with sample mean 30.0 and sample standar
klio [65]

We have a sample of 28 data points. The sample mean is 30.0 and the sample standard deviation is 2.40. The confidence level required is 98%. Then, we calculate α by:

\begin{gathered} 1-\alpha=0.98 \\ \alpha=0.02 \end{gathered}

The confidence interval for the population mean, given the sample mean μ and the sample standard deviation σ, can be calculated as:

CI(\mu)=\lbrack x-Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}},x+Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}}\rbrack

Where n is the sample size, and Z is the z-score for 1 - α/2. Using the known values:

CI(\mu)=\lbrack30.0-Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}},30.0+Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}}\rbrack

Where (from tables):

Z_{0.99}=2.33

Finally, the interval at 98% confidence level is:

CI(\mu)=\lbrack28.94,31.06\rbrack

4 0
1 year ago
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