Answer:
778.688
.........................
Answer:
fiction books = 4
non fiction books = 8
non fiction books are twice fiction books.
Step-by-step explanation:
let number of fiction books be X so
non fiction books will be 12-X
12X + 25(12-X) = 248
12X -25X = -53
X = 4( fiction books)
12-4 = 8 (non fiction)
Answer:
its D
Step-by-step explanation:
Answer:
X=50
Step-by-step explanation:
15×2=30
25×2=50
Answer:
The time interval when
is at ![1.866 \leq t \leq 3.519](https://tex.z-dn.net/?f=1.866%20%5Cleq%20t%20%5Cleq%203.519)
The distance is 106.109 m
Step-by-step explanation:
The velocity of the second particle Q moving along the x-axis is :
![V_{Q}(t)=45\sqrt{t} cos(0.063 \ t^2)](https://tex.z-dn.net/?f=V_%7BQ%7D%28t%29%3D45%5Csqrt%7Bt%7D%20cos%280.063%20%5C%20t%5E2%29)
So ; the objective here is to find the time interval and the distance traveled by particle Q during the time interval.
We are also to that :
between ![0 \leq t \leq 4](https://tex.z-dn.net/?f=0%20%5Cleq%20t%20%5Cleq%204)
The schematic free body graphical representation of the above illustration was attached in the file below and the point when
is at 4 is obtained in the parabolic curve.
So,
is at ![1.866 \leq t \leq 3.519](https://tex.z-dn.net/?f=1.866%20%5Cleq%20t%20%5Cleq%203.519)
Taking the integral of the time interval in order to determine the distance; we have:
distance = ![\int\limits^{3.519}_{1.866} {V_Q(t)} \, dt](https://tex.z-dn.net/?f=%5Cint%5Climits%5E%7B3.519%7D_%7B1.866%7D%20%7BV_Q%28t%29%7D%20%5C%2C%20dt)
= ![\int\limits^{3.519}_{1.866} {45\sqrt{t} cos(0.063 \ t^2)} \, dt](https://tex.z-dn.net/?f=%5Cint%5Climits%5E%7B3.519%7D_%7B1.866%7D%20%7B45%5Csqrt%7Bt%7D%20cos%280.063%20%5C%20t%5E2%29%7D%20%5C%2C%20dt)
= By using the Scientific calculator notation;
distance = 106.109 m