3 years ago

What’s the distance between (8,-5 ) and (6,4)

Mathematics

2 answers:

Ierofanga [76]3 years ago

6 0

Answer:

Step-by-step explanation:

d^2=(x2-x1)^2+(y2-y1)^2

d^2=(6-8)^2+(4+5)^2

d^2=4+81

d^2=85

d=(85)^(1/2)

d=9.22 (rounded to nearest hundredth)

Ber [7]3 years ago

3 0

Answer:

Approximately 9.22

Step-by-step explanation:

$Distance Formula:\\\\d=\sqrt{(x2-x1)^2+(y2-y1)^2}$

Plug in the coordinates:

$Distance Formula:\\\\d=\sqrt{(8-6)^2+(-5-4)^2}\\d=\sqrt{85}\\d=9.22$

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The point is located at P(4,7).

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To find:

The image of the given point after the translation.

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The point is translated along $\left$ . So, the rule of translation is defined by:

$(x,y)\to (x+1,y+3)$

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