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2 years ago

10 more than a number c is 3

Mathematics

1 answer:

Eddi Din [679]2 years ago

8 0

Answer:

c is -7

Step-by-step explanation:

-7 + 10 = 3

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Find the mass of an object that has a density of 1.5 g/cm^3 and has a volume<br> of 8 cm^3

Misha Larkins [42]

Answer:

Step-by-step explanation:

Find the mass of an object that has a density of 1.5 g/cm^3 and has a volume

of 8 cm^3

8 0

2 years ago

What is the relationship between area in the scale drawing and area on the on the actual tennis court if the scale is 1in.: 5ft.

sveticcg [70]

Given:

Length of the scale = 15.6 in.

Width of the scale = 7.2 in.

Scale of drawing = 1 in. : 5ft.

To find:

The ratio of area of the actual court to the area of the drawing (as a unit rate).

And to check whether it is the same as the ratio of length of the actual court to the length of the drawing.

Step-by-step explanation:

We have,

1 in. = 5ft.

Now, using this scale we get

15.6 in. = (15.6 × 5) ft =78 ft.

7.2 in. = (7.2 × 5) ft = 36 ft.

So, the actual length and width of tennis court are 78 ft and 36 ft respectively.

Area of actual tennis court is

$Area=length\times width$

$Area=78\times 36$

$Area=2808\text{ ft}^2$

The area of drawing is

$Area=15.6\times 7.2$

$Area=112.32\text{ in.}^2$

Now, ratio of area of the actual court to the area of the drawing (as a unit rate) is

$\dfrac{2808}{112.32}=\dfrac{25}{1}=25:1$

Ratio of area is 25:1 and ratio of length is 5:1 both area not same.

Therefore, the ratio of area of the actual court to the area of the drawing (as a unit rate) is 25:1.

7 0

3 years ago

Help me out please help me

Paul [167]

5x-22=3x+10
2x-22=10
2x=32
X=16

7 0

3 years ago

Marco is making mosaic garden stones using red, yellow,and blue tiles he has 45 red tiles 90 blue tiles and 75 yellow tiles. Eac

LiRa [457]

I believe it is 135 stones

45 is lowest multiplied by 3 is 135 providing equal number

8 0

2 years ago

The equation V = 16300 (0.94)^t represents the value (in dollars) of a car t years after its purchase. Use this equation to comp

Dafna1 [17]

Solution:

Given:

$V=16300(0.94)^t$

The value of a car after t - years will depreciate.

Hence, the equation given represents the value after depreciation over t-years.

To get the rate, we compare the equation with the depreciation formula.

$\begin{gathered} A=P(1-r)^t \\ \text{where;} \\ P\text{ is the original value} \\ r\text{ is the rate} \\ t\text{ is the time } \end{gathered}$

Hence,

$\begin{gathered} V=16300(0.94)^t \\ A=P(1-r)^t \\ \\ \text{Comparing both equations,} \\ P=16300 \\ 1-r=0.94 \\ 1-0.94=r \\ r=0.06 \\ To\text{ percentage,} \\ r=0.06\times100=6\text{ \%} \\ \\ \text{Hence, } \\ P\text{ is the purchase price} \\ r\text{ is the rate} \end{gathered}$

Therefore, the value of this car is decreasing at a rate of 6%. The purchase price of the car was $16,300.

5 0

10 months ago