PLS Help me in question 34 and 35
1 answer:
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Answer:
The number of students we expect to have an interval that does not contain the true mean value is, .
Step-by-step explanation:
A [100(1 - α)%] confidence interval for true parameter implies that if 100 confidence intervals are created then [100(1 - α)] of these 100 confidence intervals will consist the true population parameter value.
Here α is the significance level. It is defined as the probability rejecting the claim that the true parameter value is not included in the 100(1 - α)% confidence interval.
It is provided that 255 students create the same confidence interval, correctly.
Then the number of students we expect to have an interval that does not contain the true mean value is,
For instance, if the students are creating a 95% confidence interval for mean then the number of students we expect to have an interval that does not contain the true mean will be:
The significance level is:
Number of students we expect to have an interval that does not contain the true mean will be:
Thus, 13 of the 255 confidence intervals will not consist the true mean value.
First using the given two points we can find the slope (m) of the line
Thus the slope of given line is 1.
Using slope and a point (0,1) we can write the equation in point slope form as
y - 1= 1(x-0)
y - 1 = x
The above equation is the point-slope form of the equation.
Thus the slope of given line is 1.
Using slope and a point (0,1) we can write the equation in point slope form as
y - 1= 1(x-0)
y - 1 = x
The above equation is the point-slope form of the equation.