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Nataliya [291]
3 years ago
14

Translate this phrase into an algebraic expression. Six more than the product of 9 and Goran's age Use the variable g to represe

nt Goran's age.
Mathematics
1 answer:
aleksandrvk [35]3 years ago
6 0
9g+6 is the expression you’re looking for
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Describe the following set as either finite or infinite.
serg [7]

Answer:

infinite

Step-by-step explanation:

6 0
3 years ago
21 x ________ ÷ 3 = 21 *
GrogVix [38]

Answer:

first one: <u>3</u>

second one: <u>b</u>

third one: <u>3.2</u>

Step-by-step explanation:

first one:

21 x ________ ÷ 3 = 21

rewrite equation:

21 ÷ 3 x ___ = 21

7 x ___ = 21

(21 / 7 = 3)

7 x 3 = 21

second one:

b x h ÷ h = ___

B

third one:

876 x 3.2 ÷ ______ = 876

2803.2 ÷ ___ = 876

(2803.2 / 876 = 3.2)

2803.2 x 3.2 = 876

7 0
3 years ago
Your plan was to be on the road by 9 A.M. but you did not leave the garage until 10 A.M. You then drove with the cruise control
Wittaler [7]

Answer:

The average speed over the time interval from 9 A.M. to noon was of 33.33 mph.

Step-by-step explanation:

The average speed is given by the following equation:

v = \frac{d}{t}

From 10A.M. to noon.

You traveled at 50mph during 2 hours. So how long you traveled?

50 = \frac{d}{2}

d = 50*2

d = 100

You traveled 100 miles.

What was your average speed over the time interval from 9 A.M. to noon

From 9 A.M. to 10 A.M, you did not travel.

From 10 P.M. to noon, 100 miles.

So 100 miles during 3 hours.

v = \frac{d}{t} = \frac{100}{3} = 33.33

The average speed over the time interval from 9 A.M. to noon was of 33.33 mph.

8 0
3 years ago
EOC Review
lana [24]

Answer:

0ft and 60ft

Step-by-step explanation:

Given

The attached function

Required

Determine the valid values of the domain of the function

To do this, we simply consider the starting point and the end point of the trajectory on the x-axis (i.e. the horizontal distance).

From the attached graph, the horizontal distance starts from 0 and ends at 180.

This implies that the domain is: 0 \le x \le 180

From the options, the values that fall in this bracket are 0ft and 60ft

3 0
2 years ago
En un triángulo rectángulo A es un ángulo agudo y Sen A = 4/5 ¿Cuál será el valor de Tan A?
Nonamiya [84]

Answer:

\displaystyle \tan A=\frac{4}{3}

Step-by-step explanation:

<u>Funciones Trigonométricas</u>

La identidad principal en trigonometría es:

sen^2A+cos^2A=1

Si sabemos que A es un ángulo agudo (que mide menos de 90°), su seno y coseno son positivos.

Dado que Sen A = 4/5, calculamos el coseno:

cos^2A=1-sen^2A

Sustituyendo:

\displaystyle cos^2A=1-\left(\frac{4}{5}\right)^2

\displaystyle cos^2A=1-\frac{16}{25}

\displaystyle cos^2A=\frac{25-16}{25}

\displaystyle cos^2A=\frac{9}{25}

Tomando raíz cuadrada:

\displaystyle cos\ A=\sqrt{\frac{9}{25}}=\frac{3}{5}

La tangente se define como:

\displaystyle \tan A=\frac{sen\ A}{cos\ A}

Substituyendo:

\displaystyle \tan A=\frac{\frac{4}{5}}{\frac{3}{5}}

\displaystyle \tan A=\frac{4}{3}

6 0
3 years ago
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