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GrogVix [38]
3 years ago
12

Why can you multiply or divide both terms of a ratio by the same number without changing the value of the ratio?

Mathematics
1 answer:
LiRa [457]3 years ago
5 0
3:4 = 6:8

\frac{3}{4} =  \frac{6}{8}


The same principle is used with fractions. The identity property of multiplication states that any number times 1 is the same number. Since \frac{2}{2} = 1, the fraction/ratio does not change in value.
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Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that
kherson [118]

Answer:

The answer is

f(x) = {\displaystyle  8 + \frac{-28}{1}(x+2)+\frac{-36}{2!}(x+2)^2 + \frac{-18}{3!}(x+2)^2 }

Step-by-step explanation:

Remember that Taylor says that

f(x) = {\displaystyle \sum\limits_{k=0}^{\infty} \frac{f^{(k)}(a) }{k!}(x-a)^k }

For this case

f^{(0)} (-2) = 8(-2)-3(-2)^3 = 8\\f^{(1)} (-2) = 8-3(3)(-2)^2 = -28\\f^{(2)} (-2) = -3(3)2(-2) = -36\\f^{(2)} (-2) = -3(3)2 = -18

f(x) = {\displaystyle  8 + \frac{-28}{1}(x+2)+\frac{-36}{2!}(x+2)^2 + \frac{-18}{3!}(x+2)^2 }

5 0
3 years ago
2abc-3ab if a=2, b=-3, c=2
Elden [556K]
So a=2 since a is next to the first 2 it would be 2x2 which equals 4 next it’s B and B= -3 so -3x4 equals -12 and then c also equals 2 so it would be -12x2 and that equals -24. Moving on to the next part as I said a=2 so it would be 3x2 and that equals 6 next it’s B again so 6x -3 equals -18 so now take -24 and -18 and subtract them and you would get -6. Sorry if this answer is wrong I did my best...hope it helped.
5 0
3 years ago
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