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3 years ago

Why can you multiply or divide both terms of a ratio by the same number without changing the value of the ratio?

1 answer:

5 0

3:4 = 6:8

$\frac{3}{4} = \frac{6}{8}$

The same principle is used with fractions. The identity property of multiplication states that any number times 1 is the same number. Since $\frac{2}{2}$ = 1, the fraction/ratio does not change in value.

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Srekar needs to increase the size of the prism below by 2 inches on each side. The original prism has a length of 3, a depth of

Leto [7]

Answer:

a b

Step-by-step explanation:

The options as obtained from the internet.

- the new prism will have a length of 5

- the new prism will have a depth of 4

- the new prism will have a height of 2

- the volume will increase by 6 and each of the 3 dimensions is increased by 2.

- srekar could increase the volume by the same amount by just adding 6 to the height instead of 2 to each side

The volume of a rectangular prism is (length × depth × height)

Originally, length = 3 inches

Depth = 2 inches

Height = 1 inch

Original volume = 3×2×1 = 6 in³

Then, Sreka adds 2 inches to each of the dimensions,

New length = 3+2 = 5 inches

New depth = 2+2 = 4 inches

New height = 1+2 = 3 inches

New volume = (5×4×3) = 60 in³

Taking each of the statements one at a time

Statement 1

the new prism will have a length of 5

True!

Statement 2

the new prism will have a depth of 4

True!

Statement 3

the new prism will have a height of 2

False! New height = 3 inches

Statement 4

the volume will increase by 6 and each of the 3 dimensions is increased by 2.

This is false. The volume increased to 10 folds of its original volume.

Statement 5

srekar could increase the volume by the same amount by just adding 6 to the height instead of 2 to each side

Adding 6 inches to the height,

New height = 1+6 = 7 inches

New volume = 3×2×7 = 42 in³

This statement is false as the new volume from adding 2 inches to each side is 60 in³

Hope this Helps!!!

5 0

3 years ago

Ms. Johnson owns a cabinet business that installs cabinets in kitchens. Her employees can install 2/3 of a kitchen cabinet set i

dmitriy555 [2]

Answer:

I don't know

Step-by-step explanation:

8 0

3 years ago

I need help to solve this problem p/0,05p

AfilCa [17]

p / 0.05p

= 1 / 0.05

= 20 answer

7 0

3 years ago

Let f(x)=x2−2x−4 . What is the average rate of change for the quadratic function from x=−1 to x = 4?

goblinko [34]

Answer:

The average rate of change for f(x) from x=−1 to x = 4 is, 1

Step-by-step explanation:

Average rate A(x) of change for a function f(x) over [a, b] is given by:

$A(x) = \frac{f(b)-f(a)}{b-a}$

As per the statement:

$f(x) = x^2-2x-4$

we have to find the average rate of change from x = -1 to x = 4

At x = -1

$f(-1) = (-1)^2-2(-1)-4 = 1+2-4 = -1$

and

at x = 4

$f(4) = (4)^2-2(4)-4 = 16-8-4 = 4$

Substitute these in [1] we have;

$A(x) = \frac{f(4)-f(-1)}{4-(-1)}$

⇒ $A(x) = \frac{4-(-1)}{4+1}$

⇒ $A(x) = \frac{5}{5}$

Simplify:

A(x) = 1

Therefore, the average rate of change for f(x) from x=−1 to x = 4 is, 1

4 0

3 years ago

Read 2 more answers

This is a System Of Equations and I'd like it to get solved by the Elimination or Substitution Method.x+2y=83x+5y=8

Sonbull [250]

Answer:

x=133 y=-25

Step-by-step explanation:

I'll do both ways for you. So let's start with Substitution:

With the sub method, you have to set both equations equal to each other by setting them equal to the same variable. Since there is no coefficient in front of both x's in both equations, that variable will be easiest to solve for.

x + 2y = 83 & x + 5y = 8

Solve for x.

x = 83 - 2y & x = 8 - 5y

Once you have solved for x, set each equation equal to one another and solve for y now.

83 - 2y = 8 - 5y

Isolate all variables to one side:

83 = 8 - 3y

Now subtract the 8 to fully isolate the y variable:

75 = -3y

Divide by -3:

-25 = y Now that you have your first variable, plug it into one of the original equations and solve for x.

x + 2(-25) = 83

x - 50 = 83

x = 133

Now for the Elimination method. For this method you need to get rid of a variable by either subtracting/adding each equation together. Again, since you can subtract and x from both equations, you will be left with only the y variable to solve:

Put each equation on top of one another and subtract:

x + 2y = 83

- (x + 5y = 8)

The x's will cancel out:

(x - x) + (2y - 5y) = (83 - 8)

Simplify:

-3y = 75

Solve for y

y = -25

Then, plug y = -25 into one of the original equations:

x + 5(-25) = 8

Solve for x:

x - 125 = 8

x = 133

Hope this helps!

8 0

2 years ago