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Alexeev081 [22]

3 years ago

11

Using the formula calculate the value of an initial investment of $4,500 after 10 years at 4% interest, compounded quarterly (fo

ur times per year).

1 answer:

m_a_m_a [10]3 years ago

8 0

Answer:

A = P(1 + r/n) ^nt

4500 x (1 + (4/100)/4)^(10 x 4)

4500 x (1.01)^40

6699.89$

Step-by-step explanation:

You might be interested in

Factor the expression 9x^2-4

bezimeni [28]

$9x^2 - 4 \\ \\ (3x)^2 - 2^2 \\ \\ (3x+2)(3x-2) \\ \\ Answer: \fbox {(3x+2)(3x-2)}$

7 0

3 years ago

Can you explain how to solve this please?

givi [52]

9514 1404 393

Answer:

-25

Step-by-step explanation:

Consult your memory of multiplication tables to determine the square root of 100.

10×10 = 100

√100 = 10

Then multiply that value by -2.5

-2.5×10 = -25

___

Of course, you can use a calculator or spreadsheet to evaluate this expression, too.

6 0

3 years ago

How do you solve the system of elimination method. x-6y=-30 -2x-5y=-25

AlexFokin [52]

X-6y=-30...equatn 1
-2x-5y=-25....equatn 2
multiply eqn 1 and 2 with 5 and 6 respectively
5x-30y=-150
-12x-30y=-150
subtract to eliminate y
17x=0
x=0
substitute x=0 into any of the equations
0-6y=-30
-6y=-30
y=-30/-6
y=5
x=0;y=5

8 0

3 years ago

Read 2 more answers

What is the following product?

Zarrin [17]

Answer: A

Step-by-step explanation:

$(\sqrt{12}+\sqrt{6})(\sqrt{6}-\sqrt{10})$

$(\sqrt{12}*\sqrt{6})-(\sqrt{12}* \sqrt{10})+(\sqrt{6}*\sqrt{6})-(\sqrt{6}*\sqrt{10})$

$(\sqrt{12*6})-(\sqrt{12*10})+(\sqrt{6*6})-(\sqrt{6*10})$

Let's rewrite the numbers inside to see if we can take some out.

For example; 12 is 3 x 4 and 4 is $2^2$ which means a 2 will come out of the root.

$(\sqrt{3*2^2*6})-(\sqrt{3*2^2*10})+(\sqrt{6^2})-(\sqrt{6*10})$

$(2\sqrt{18})-(2\sqrt{30})+(6)-(\sqrt{60})$

We can also rewrite 18 as 9 x 2 and 9 can be rewritten as $3^2$ which will make the 3 come out.

60 can be rewritten as 15 x 4 and 4 can be rewritten as $2^2$ which will make the 2 come out.

Let's rewrite this.

$(2\sqrt{2*3^2})-(2\sqrt{30})+(6)-(\sqrt{15*2^2})$

When a number comes out of a root, it has to be multiplied by the number that is already outside.

$(2*3\sqrt{2})-(2\sqrt{30})+(6)-(2\sqrt{15})$

Solve and eliminate parentheses.

$6\sqrt{2}-2\sqrt{30}+6-2\sqrt{15}$

6 0

3 years ago

Find the total area the regular pyramid.<br><br><br><br> T. A. =

alexira [117]

The answer would be A = 54raiz (3) + 18raiz (91)
Formula:
A = Ab + Al Where, Ab=base area A= lateral area

The area of the base is: Ab = (3/2) * (L ^ 2) * (root (3)) Where, L= side of the hexagon. Substitute: Ab = (3/2) * (6 ^ 2) * (root (3)) Ab = (3/2) * (36) * (root (3)) Ab = 54raiz (3)

The lateral area is: Al = (6) * (1/2) * (b) * (h) Where, b= base of the triangle h= height of the triangle Substitute: Al = (6) * (1/2) * (6) * (root ((8) ^ 2 + ((root (3) / 2) * (6)) ^ 2)) Al = 18 * (root (64 + 27)) Al = 18raiz (91)

The total area is: A = 54raiz (3) + 18raiz (91)

6 0

4 years ago

Read 2 more answers