2 years ago

Help! i need an equation for this

Mathematics

1 answer:

Nataly [62]2 years ago

7 0

Answer:

y = -2/3x + 8

Step-by-step explanation:

Format: y = mx + b

m = slope (rise over run) - 2/3 The graph is negative so the slope is also negative.

b = y - intercept (8)

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Use lagrange multiplier techniques to find the local extreme values of f(x, y) = x2 − y2 − 2 subject to the constraint x2 + y2 =

dexar [7]

Given $f(x,\ y)=x^2-y^2-2$ subject to the constraint $x^2+y^2=16$

Let $g(x,\ y)=x^2+y^2$ .

The gradient vectors of $f$ and $g$ are:

$\nabla f(x,\ y)=\langle2x,-2y\rangle$ and $\nabla g(x,\ y)=\langle2x,2y\rangle$

By Lagrange's theorem, there is a number $\lambda$ , such that

$\langle2x,-2y\rangle=\lambda\langle2x,2y\rangle=\langle2\lambda x,2\lambda y\rangle$

$\lambda=\pm1$

It can be seen that $f(x,\ y)=x^2-y^2-2$ has local extreme values at the given region.

6 0

3 years ago

(PLEASE HELP!!)

AlexFokin [52]

Answer:

X= 8

Y= 130

(8, 130)

Step-by-step explanation:

I used a graphing calculator to see where the two equations intersected.

Hope this helped :)