What is -3 and 5/7 expressed as an improper fraction?
1 answer:
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Answer:
(f+g)(2) = 4
(f-g)(4) = 8
(f ÷g)(2) = 7
(f x g)(1) = 0
Step-by-step explanation:
We are given these following functions:
(f+g)(2)
At
Then
(f+g)(2) = 4
(f-g)(4)
At x = 4
Then
(f-g)(4) = 8
(f ÷g)(2)
At x = 2
Then
(f ÷g)(2) = 7
(f x g)(1)
Then
So
(f x g)(1) = 0
If 
is odd, then
while if is even, then the sum would be
The latter case is easier to solve:
which means
.
In the odd case, instead of considering the above equation we can consider the partial sums. If is odd, then the sum of the even integers between 1 and would be
Now consider the partial sum up to the second-to-last term,
Subtracting this from the previous partial sum, we have
We're given that the sums must add to
, which means
But taking the differences now yields
and there is only one for which 
; namely, 
. However, the sum of the even integers between 1 and 5 is 
, whereas 
. So there are no solutions to this over the odd integers.
while if
The latter case is easier to solve:
which means
In the odd case, instead of considering the above equation we can consider the partial sums. If
Now consider the partial sum up to the second-to-last term,
Subtracting this from the previous partial sum, we have
We're given that the sums must add to
But taking the differences now yields
and there is only one