Find the slope of this line
slope=(y2-y1)/(x2-x1)
slope=(-9-(-4))/(0-(-3))=(-9+4)/(3)=-5/3
yint is y=-9
y=mx+b
y=-5/3x-9
parllell means has same slope
y=-5/3x+b
find b by inputing point
(3,-7)
(x,y)
x=3
y=-7
-7=-5/3(3)+b
-7=-5+b
add 5
-2=b
the equation of the line is y=-5/3x-2
42,42,24,36,60,6
1st Find the mean X̅
=(42+42+24+36+60+6)/6 = 35
2nd find the difference between the data set value and the mean (x - X̅)
and square them:
(42-35)² = 49
(42-35)² = 49
(24-35)² = 121
(36-35)² = 1
(60-35)² = 625
(6-35)² = 814
Now add up te result ∑(x-X̅)² =1659
The lesser one is -4 and the greater x is 0.5
The thing that is true about -5 and 5 is the answer is zero.
Y1-y2 over x1- x2 you should be able to figure it out after this formula
