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DiKsa [7]
3 years ago
9

Is x = 1 the solution to 3(x + 3) = 8 - 2x (show me why! Or maybe why not)

Mathematics
1 answer:
monitta3 years ago
4 0

Answer:

3(1+3) = 8-2

12 = 6

therefore x is not equal to 1.

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Can someone please help me​
zmey [24]

Answer:

C

Step-by-step explanation:

8 0
3 years ago
Estimate. then find the sum. 1.20 plus 0.34
Trava [24]
1.20 + 0.34 = 1.54
That is the answer.
5 0
3 years ago
Read 2 more answers
Sketch the algebra-tile shape at right on your paper. Write an expression for the
Dima020 [189]

Answer:

Part 1) P=(4x+4)\ units

Part 2)

a) P=32\ units

b) P=26\ units

c) P=13\frac{1}{3}\ units

Step-by-step explanation:

<u><em>The complete question in the attached figure</em></u>

Part 1) Write an expression for the  perimeter of the shape

we know that

The figure is composed by a larger square, a rectangle and a smaller square

1) The area of the larger square is given

A=x^2\ units^2

so

The length and the width of the larger square is x units

2) The area of the rectangle is given

A=x\ units^2

so

The length of the rectangle is x units and the width is 1 unit

3) The length and the width of the smaller square is x units

see the attached figure N 2 to better understand the problem

Find out the perimeter

The perimeter is the sum of all the sides.

so

P=(x+x+x+x+1+1+1+1)

P=(4x+4)\ units

Part 2) Find the perimeter for each of the given values of x.

a) For x=7 units

Substitute the value of x in the expression of the perimeter

P=(4(7)+4)=32\ units

b) For x=5.5 units

Substitute the value of x in the expression of the perimeter

P=(4(5.5)+4)=26\ units

b) For x=7/3 units

Substitute the value of x in the expression of the perimeter

P=(4(\frac{7}{3})+4)=\frac{40}{3}=13\frac{1}{3}\ units

8 0
3 years ago
If LM = 20 cm, and PQ = 16 cm, what is the length of RM, in centimeters?
LuckyWell [14K]

Answer:

RM = 12 cm

Step-by-step explanation:

a^{2} + b^{2} = c^{2}

Assuming 20 is the hypotenuse cus there is no picture:

a^{2} + 16^{2} = 20^{2}

a^{2} +256 = 400

a^{2} = 144

a=144

If It's not the hypotenuse:

16^{2}+ 20^{2} =c^{2}

256+400 =c^{2}

656=c^{2}

c = 25.61249695

But I find it unlikely that 20 wasn't the hypotenuse so ignore that unless it applies.

Hope this helped. :0)

5 0
3 years ago
How do you solve this?
Katarina [22]

\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{}{ h},\stackrel{}{ k})\qquad \qquad radius=\stackrel{}{ r} \\\\[-0.35em] ~\dotfill\\\\ (x-6)^2+(y+5)^2=16\implies [x-\stackrel{h}{6}]^2+[y-(\stackrel{k}{-5})]^2=\stackrel{r}{4^2}~\hfill \begin{cases} \stackrel{center}{(6,-5)}\\ \stackrel{radius}{4} \end{cases}

Check the picture below.

6 0
4 years ago
Read 2 more answers
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