Since <em>l</em> and <em>m</em> are parallel, the unlabeled angle adjacent to the 63° one also has measure (7<em>x</em> - 31)° (it's a pair of alternating interior angles).
Then the three angles nearest line <em>m</em> are supplementary so that
(7<em>x</em> - 31)° + 63° + (5<em>x</em> - 8)° = 180°
Solve for <em>x</em> :
(7<em>x</em> - 31) + 63 + (5<em>x</em> - 8) = 180
12<em>x</em> + 24 = 180
12<em>x</em> = 156
<em>x</em> = 13
The bottom-most angle labeled with measure (4<em>y</em> + 27)° is supplementary to the angle directly adjacent to it, so this unlabeled angle has measure 180° - (4<em>y</em> + 27)° = (153 - 4<em>y</em>)°. The interior angles of any triangle have measures that sum to 180°, so we have
(7<em>x</em> - 31)° + 63° + (153 - 4<em>y</em>)° = 180°
We know that <em>x</em> = 13, so 7<em>x</em> - 31 = 60. Then this simplifies to
123° + (153 - 4<em>y</em>)° = 180°
Solve for <em>y</em> :
123 + (153 - 4<em>y</em>) = 180
276 - 4<em>y</em> = 180
96 = 4<em>y</em>
<em>y</em> = 24
The equation in slope-intercept is y=0.625x+7.
y = mx + b
where:
m is the slope of the line
b is the y-intercept of the line
The slope m of the line through any two points (x1, y1) and (x2, y2) is given by:
The y-intercept b of the line is the value of y at the point where the line crosses the y axis. Since for point (x1, y1) we have y1 = mx1 + b, the y-intercept b can be calculated by:
b = y1 - mx<span>1. hope that helped</span>
Answer:
1.25(-xsquare - 8x + 16)
Step-by-step explanation:
pls give me brainliest
I'm not sure but I think so
Answer:
See below
Step-by-step explanation:
Let's take it part by part:
(3-4)+(11+21)-3
-1+(32)-3
-4+32
28