Question

Help please! Would mean so much to me<3

Answer 1

So:
(x-4)(x+2) / (x-4)(x+4)
We cancel out the x - 4:
(x+2)/(x+4)
Restrictions: x ≠ 4, x ≠ -4

Answer 2

$\dfrac{x^2-2x-8}{x^2-16} = \dfrac{ (x + 2)(x - 4)}{(x-4)(x+4)} = \dfrac{x+2}{x+4}$

$\boxed {\boxed{\text{Answer :} \dfrac{x+2}{x+4} , x \neq -4 }}$