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Marat540 [252]
2 years ago
6

You are randomly selecting 3 cans of regular and diet cola, but assume that there are 6 cans of regular cola and 7 cans of diet

cola.
What is the probability that 2 cans of regular cola and 1 can of diet cola are selected?
Mathematics
1 answer:
gayaneshka [121]2 years ago
6 0

Answer:0.367

Step-by-step explanation:

Given

There are 6 cans of regular and 7 cans of diet cola

number of ways of selecting 2 regular colas and 1 can of diet cola is

\Rightarrow ^6C_2\times ^7C_1

The total no of ways of selecting 3 items out of 13 items is

\Rightarrow ^{13}C_3

Probability is

\Rightarrow P=\dfrac{^6C_2\times ^7C_1}{^{13}C_3}=\dfrac{105}{286}\\\Rightarrow P=0.367

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What are the solutions to the equation?<br> 7x^3=28x
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7x³ = 28x is our equation. We want its solutions.

When you have x and different powers, set the whole thing equal to zero.

7x³ = 28x

7x³ - 28x = 0

Now notice there's a common x in both terms. Let's factor it out.

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2 years ago
Two balls are chosen randomly from an urn containing 8 white, 4 black, and 2 orange balls. Suppose that we win $2 for each black
MA_775_DIABLO [31]

Answer:

The objective of the problem is obtained below:

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5 0
3 years ago
Will mark brainliest to whoever answers correctly first!!!
IgorLugansk [536]
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hope I helped ;)
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2 years ago
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