Ask question

Ask question

All categories

2 years ago

9

Last week, Brianna earned $565.75, which included a $100 bonus. She makes $11.50 an hour. Which equation and solution can be use

d to show how many hours Brianna worked last week?

1 answer:

cluponka [151]2 years ago

3 0

Its 677.25 hope it helps

You might be interested in

Help! What is the answer to: <br> 4x^2 + 9x - 1 = 0

nataly862011 [7]

I hope this helps you

a=4

b=9

c= -1

disctirminant =b^2-4ac

disctirminant =9^2-4.4. (-1)

disctirminant =97

x1=-9+square root of 97/2.4= -9+square root of 97/8

x2= -9-square root of 97/2.4= -9-square root of 97/8

6 0

2 years ago

Read 2 more answers

Valentin [98]

Answer:

15 to 21

Step-by-step explanation:

junk to total

4 0

2 years ago

Solve the following inequalities (picture attached)

11Alexandr11 [23.1K]

34.
(a) A. x < 4
(b) p > 1
(c) y <span>≤ 2.8

I love solving inequalities. I hope you find this answer the most helpful! :)</span>

6 0

2 years ago

Brainlist<br> Please help me

creativ13 [48]

Answer:

Yes she made an error. Explanation is below.

Step-by-step explanation:

Let the sample space for a six sided number cube be S

$n(S) = \{1,2,3,4,5,6\}\\n(S) = 6$

Let the event of a number getting greater than two be B

$n(B) = \{3,4,5,6\}\\n(B) = 4$

To find:

the probability of complement of B that is

p(~B) = ?

Solution"

First we need to solve probability for number getting greater than two

$p(B) = \frac{n(B)}{n(S)}$

Now substituting the values we get

$p(B) = \frac{4}{6}$

$p(B) = \frac{2}{3}$

but we need complement of B so

$p(\textrm{complement of B)} = 1 - p(B)\\p(\~B) = 1 - p(B)\\p(\~B) = 1 - \frac{2}{3}\\ =\frac{1}{3} \\$

P(complement of rolling a number greater than two) = $\frac{1}{3}$

3 0

3 years ago

Apply the distributive property to create an equivalent expression.

weqwewe [10]

Step-by-step explanation:

$\text{The distributive property:}\ a(b+c)=ab+ac\\\\\dfrac{1}{2}(10x+20y+10z)=\dfrac{1}{2\!\!\!\!\diagup_1}\cdot10\!\!\!\!\!\diagup^5x+\dfrac{1}{2\!\!\!\!\diagup_1}\cdot20\!\!\!\!\!\diagup^{10}y+\dfrac{1}{2\!\!\!\!\diagup_1}\cdot10\!\!\!\!\!\diagup^5z\\\\=5x+10y+5z$

6 0

2 years ago