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3 years ago

Please answer! You’ll get brainliest:)) please show your evidence! :)

Mathematics

1 answer:

makkiz [27]3 years ago

4 0

. . . . . . . . . . .
. . . , . L , . . ?

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What percent of 92 is 69

11Alexandr11 [23.1K]

63.58 percent or 63.6 percent

4 0

4 years ago

Read 2 more answers

How to solve p/6=92 worked out so I understand

elena-s [515]

Hello,

$\frac{p}{6}=92$

we multiply both sides by 6:

$\frac{p}{6}*6=92*6 \\ \\ p=552$

Answer: p=552

6 0

3 years ago

5 positive integers that have a mode of 2, a median of 5, a mean of 6 and a range of 10.

liubo4ka [24]

The numbers should be 2, 2, 5, 9 and 12.

<h3>What is mean, mode and median?</h3>

The arithmetic mean is found by adding the numbers and dividing the sum by the number of numbers in the list.

The median is the middle value in a list ordered from smallest to largest. The mode is the most frequently occurring value on the list.

Let us take numbers 2, 2, 5, 9 and 12.

Mean = 192+2+5+9+12)/5

mean = 30/5

mean= 6

mode = 2

median = 5

range = 12-2

range = 10.

Learn more about mean, mode and median here:

brainly.com/question/15323584

#SPJ1

3 0

2 years ago

Which of the following equations are equivalent to -2m - 5m - 8 = 3 + (-7) + m?

noname [10]

B. The answer is b because -2m and -5m together equal -7m-8, and on the other side of the equal sign 3+-7+m equal -4+m

4 0

4 years ago

Mean and Standard Deviation of Senior Citizens In the 2010 US Census, we learn that of all people in the US are senior citizens.

cluponka [151]

Answer:

The mean of X is 1.17.

The standard deviation of X is 1.009.

Step-by-step explanation:

<em>The question is incomplete: 1ean and Standard Deviation of Senior Citizens In the 2010 US Census, we learn that of all people in the US </em><em>13% </em><em>are senior citizens. Let the random variable X represent the number of senior citizens in a random sample of 9 people. Find the mean and standard deviation of this random variable. Enter the exact answer for the mean, and round your answer for the standard deviation to three decimal places.</em>

<em />

This variable X can be modeled as a binomial random variable, with n=9 and p=0.13.

The mean of X is:

$\mu=np=9*0.13=1.17$

The standard deviation of X is:

$\sigma=\sqrt{npq}=\sqrt{9*0.13*0.87}=\sqrt{1.0179}=1.009$

3 0

3 years ago