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yaroslaw [1]
3 years ago
10

How do I solve an equation with different variables on both sides? here is an example.

Mathematics
1 answer:
Goryan [66]3 years ago
8 0

Answer:

Step-by-step explanation:

9x - 2c = k

    9x = k + 2c

     x  = (k + 2c)/9

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What is the volume of this container? <br><br> please helppp!!!!!
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3 years ago
triangle abc is rotated 90° clockwise about the origin. what is the rules that we can use to find the vertices location of the i
yuradex [85]

Answer:

The answer is when we rotating something 90 degrees clockwise about the orgin

(x,y) goes to (y,-x)

5 0
3 years ago
Simplify 8r+(-4r)+3 and then solve if r=5​
timama [110]

Simplify= 4r+3

Because 8r plus -4r which is 4r and then 3 can’t be simplified so u keep it the same

Then the answer if r=5 is 23

Because the equation looks like 4(5)+3

5 times 4 is 20 plus 3 is 23

7 0
3 years ago
(secx)dy/dx=e^(y+sinx), please help me solve the differential equation. Thanks :)
nalin [4]
First, you must know these formula  d(e^f(x) = f'(x)e^x dx, e^a+b=e^a.e^b, and d(sinx) = cosxdx, secx = 1/ cosx

(secx)dy/dx=e^(y+sinx), implies  <span>dy/dx=cosx .e^(y+sinx), and then 
</span>dy=cosx .e^(y+sinx).dx, integdy=integ(cosx .e^(y+sinx).dx, equivalent of 
integdy=integ(cosx .e^y.e^sinx)dx, integdy=e^y.integ.(cosx e^sinx)dx, but we know that   d(e^sinx) =cosx e^sinx dx,
so integ.d(e^sinx) =integ.cosx e^sinx dx,
and e^sinx + C=integ.cosx e^sinxdx
 finally, integdy=e^y.integ.(cosx e^sinx)dx=e^2. (e^sinx) +C
the answer is 
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7 0
3 years ago
Read 2 more answers
1/3 ( x - 10) = -4 ???​
Pepsi [2]

Answer:

x =  - 2

Step-by-step explanation:

1) Simplify 1/3 ( x - 10) to x-10/3.

\frac{x - 10}{3}  =  - 4

2) Multiply both sides by 3.

x - 10 =  - 4 \times 3

Simplify 4 × 3 to 12.

x - 10 =  - 12

4) Add 10 to both sides.

x =  - 12 + 10

5) Simplify -12 + 10 to -2.

x =  - 2

So, therefor, the answer is, x = -2.

4 0
3 years ago
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