Answer:
The correct option is b) 1.70
Step-by-step explanation:
Consider the provided information.
The weekly sulfur dioxide emissions follow a normal distribution with a mean of 1000 ppm (parts per million) and a standard deviation of 25.
Thus, μ=1000 and σ = 25
The CEO wants to know if the mean level of emissions is different from 1000.
Therefore the null and alternative hypothesis is:
and ![H_a:\mu \neq1000](https://tex.z-dn.net/?f=H_a%3A%5Cmu%20%5Cneq1000)
The sample size is n = 50 and
ppm.
Now calculate the test statistic by using the formula: ![z=\frac{\bar x-\mu}{\frac{\sigma}{\sqrt{n}}}](https://tex.z-dn.net/?f=z%3D%5Cfrac%7B%5Cbar%20x-%5Cmu%7D%7B%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%7D)
Substitute the respective values in the above formula.
![z=\frac{1006-1000}{\frac{25}{\sqrt{50}}}](https://tex.z-dn.net/?f=z%3D%5Cfrac%7B1006-1000%7D%7B%5Cfrac%7B25%7D%7B%5Csqrt%7B50%7D%7D%7D)
![z=\frac{6}{\frac{25}{\sqrt{50}}}=1.697\approx 1.70](https://tex.z-dn.net/?f=z%3D%5Cfrac%7B6%7D%7B%5Cfrac%7B25%7D%7B%5Csqrt%7B50%7D%7D%7D%3D1.697%5Capprox%201.70)
Hence, the correct option is b) 1.70
A= -18
B= -27
12-39=-27
These should be the answers
This question was answered but no solution was given.
We already solve for the B or area of the triangular base which was 5.25cm².
There are 2 triangular faces in the prism so 5.25cm² x 2 = 10.50cm²
There are 3 rectangular face in the prism, we need to get the area of each.
area of a rectangle = length x width
rectangle 1: 5 cm x 4 cm = 20 cm²
same dimension with rectangle 2. so, area is 20 cm² also
rectangle 3: 5 cm x 2.8 cm = 14 cm²
let us all add up the area of each surface.
2 triangle = 10.50 cm²
3 rectangles = 20 cm² + 20 cm² + 14 cm² = 54 cm²
10.50 cm² + 54 cm² = 64.50 cm²
444.25(8) = 3554
4000 - 3554 = 446 <== what she still owes