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2 years ago

Factor 7x^4 - 63please I can't afford to fail my homework

Mathematics

1 answer:

Dmitrij [34]2 years ago

4 0

7(x^2+3)(x^2-3)
I used mathpapa.com
Hope this helps!

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(4-9-8)÷3×3please help AFAP

Elenna [48]

Answer:

I am not really sure but try this -13/9 or -13 divided by 9

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

The Caesar Cipher of the sentence "THIS MESSAGE IS TOP SECRET."

vagabundo [1.1K]

Answer: Option 'a' is correct.

Step-by-step explanation:

Since we have given that

"THIS MESSAGE IS TOP SECRET."

We need to use the Caesar cipher.

As in general we always take a shift of 3 keys in Caesar cipher.

so, According to shift of 3 keys it becomes,

T→W

H→K

I→L

S→V

M→P

E→H

A→D

G→J

O→R

C→F

R→U

P→S

So, it can be written as

"THIS MESSAGE IS TOP SECRET."

WKLVP HVVDJ HLVWR SVHFU HW.

we make a set of 5 letters in a word after Caesar cypher.

Hence, Option 'a' is correct.

8 0

2 years ago

2/3 - 1/5<br>answer pls

Sedbober [7]

The answer would be 7/15

3 0

2 years ago

Two rectangles have the exact same area. The measurements of the first rectangle are: length = 3k and width = 3 And the measurem

lions [1.4K]

Answer:

Step-by-step explanation:

because

5 0

2 years ago

1. if csc β = 7/3 and cot β = - 2√10 / 3, Find sec β

slava [35]

Step-by-step explanation:

$\tan \beta = \frac{1}{ \cot \beta } = - \frac{3}{2 \sqrt{10} } = - \frac{3 \sqrt{10} }{20}$

$\csc \beta \tan \beta = \frac{1}{ \cos \beta } = \sec \beta$

Therefore,

$\sec \beta = ( \frac{7}{3} )( - \frac{3 \sqrt{10} }{20} ) = - \frac{7 \sqrt{10} }{20}$

$\csc y = \frac{1}{ \sin y} = - \frac{ \sqrt{6} }{2}$

$= > \sin y = - \frac{ \sqrt{6} }{3}$

Use the identity

$\cos y = \sqrt{1 - \sin ^{2} y} \: \: \: \: \: \: \: \: \: \: \: \\ = \sqrt{1 - {( - \frac{ \sqrt{6} }{3}) }^{2} } = - \frac{ \sqrt{3} }{3}$

We chose the negative value of the cosine because of the condition where cot y > 0. Otherwise, choosing the positive root will yield a negative cotangent value. Now that we know the sine and cosine of y, we can now solve for the tangent:

$\tan \beta = \frac{ \sin y}{ \cos y} =( - \frac{ \sqrt{6} }{3} )( - \frac{3}{ \sqrt{3} } ) = \sqrt{2}$

3. Recall that sec x = 1/cos x, therefore cos x = 5/6. Solving for sin x,

$\sin x = \sqrt{1 - \cos ^{2} x} = \sqrt{ \frac{11}{6} }$

Solving for tan x:

$\tan x = \frac{ \sin x}{ \cos x} = (\frac{ \sqrt{11} }{ \sqrt{6} } )( \frac{6}{5} ) = \frac{ \sqrt{66} }{5}$

5 0

2 years ago