Answer:
Positive: (-3)4,(-1)2,(-4)8
Negative:(-10)5,(-2)9,(-6)3
Step-by-step explanation:
Answer:
<-|---------------|----------------|--------------|->
0 1/3 2/3 1
Step-by-step explanation:
easy peasy
Answer:
The correct option is A.
Step-by-step explanation:
Domain:
The expression in the denominator is x^2-2x-3
x² - 2x-3 ≠0
-3 = +1 -4
(x²-2x+1)-4 ≠0
(x²-2x+1)=(x-1)²
(x-1)² - (2)² ≠0
∴a²-b² =(a-b)(a+b)
(x-1-2)(x-1+2) ≠0
(x-3)(x+1) ≠0
x≠3 for all x≠ -1
So there is a hole at x=3 and an asymptote at x= -1, so Option B is wrong
Asymptote:
x-3/x^2-2x-3
We know that denominator is equal to (x-3)(x+1)
x-3/(x-3)(x+1)
x-3 will be cancelled out by x-3
1/x+1
We have asymptote at x=-1 and hole at x=3, therefore the correct option is A....
Answer:
do length times width times height and see what you get if your answer is not on there split the figure into 2 shapes and do l*w*h to both and add you 2 figures together then see if you have your answer.
Step-by-step explanation:
do length times width times height and see what you get if your answer is not on there split the figure into 2 shapes and do l*w*h to both and add you 2 figures together then see if you have your answer. hope that helps!
Answer:
{(0,0),(0,1),(1,2),(1,3)}
Step-by-step explanation:
If this was a function it would be (0,0) ,(1,1), (2,2) ,(3,3) and so on
