<img src="https://tex.z-dn.net/?f=9%20%20%5Ctimes%20%20%5Cfrac%7B3%7D%7B4%7D%2012" id="TexFormula1" title="9 \times \frac{3}{4

Mrac [35]

2 years ago

} 12" alt="9 \times \frac{3}{4} 12" align="absmiddle" class="latex-formula">
pleaseee helppp

Mathematics

2 answers:

kow [346]2 years ago

7 0

$9 \times 3 \times \frac{12}{4} = 9 \times 3 \times 3 = 81$

iogann1982 [59]2 years ago

3 0

$9\times \cfrac{3}{4}12\implies \cfrac{9\cdot 3\cdot 12}{4}\implies \cfrac{9\cdot 3}{1}\cdot \cfrac{12}{4}\implies \cfrac{27}{1}\cdot \cfrac{3}{1}\implies \cfrac{81}{1}\implies 81$

You might be interested in

Help me with this question i tried multiple time to solution it always wrong

maw [93]

7/9-1/3 or 7/9-3/9= 4/9 is the answer

4 0

3 years ago

Solve for r. 42<6-3r<_24<br> Pls help it’s due today

Alika [10]

Answer:

r < -12 and r > -6

Step-by-step explanation:

7 0

3 years ago

If you flip the five coins, and the probability of one coin being "tails" is 0.50, what is the probability of getting "tails" on

jenyasd209 [6]

Answer: 0.03125

Step-by-step explanation:

We know that the probability of getting a tail , we toss a fair coin = 0.5

Given : Total number of trials = 5

Using binomial probability formula :

$P(x)=^nC_xp^x(1-p)^{n-x}$ , where P(x) is the probability of getting success in x trails, n is total number of trials and p is the probability of getting success in each trial.