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Pani-rosa [81]
3 years ago
11

Help me out please and dont send suspicious links

Mathematics
2 answers:
Lena [83]3 years ago
7 0

Step-by-step explanation:

I think B or F is the best answer

babymother [125]3 years ago
6 0

Answer:

The answer is b

Step-by-step explanation:

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Aiden bought 15 chicken wings for $10. What was the cost of the wings in wings per dollar?
Verdich [7]

Answer: $1.50

Step-by-step explanation:

15/10=1.5

6 0
2 years ago
Read 2 more answers
Write an equation for the sentence "The product of a number n and 7.7 equals 112.42." Solve for the variable.
pishuonlain [190]

Answer:

7.7n=112.42

n=14.6

Step-by-step explanation:

The product is the result obtained by multiplying two factors. Then, the sentence ""The product of a number n and 7.7 equals 112.42" can be expressed with the following equation:

7.7n=112.42

To solve for the variable "n", you has two apply the Division property of equality and divide both sides of the equation by 7.7

Therefore, the value of "n" is:

\frac{7.7n}{7.7}=\frac{112.42}{7.7}\\\\n=14.6

8 0
3 years ago
A set of angles has a ratio of 5 to 2. If the larger angle measures 105 degrees then what is the measure of the smaller angle
bekas [8.4K]

ratio 5:2

105, ___

5x = 105 → x = 21

2x = ____ → 2(21) = 42

Answer: 42°

6 0
3 years ago
Read 2 more answers
Our faucet is broken, and a plumber has been called. The arrival time of the plumber is uniformly distributed between 1pm and 7p
Ymorist [56]

Answer:

E(A+B) = E(A)+E(B)=4+0.5 =4.5 hours

Var(A+B)= Var(A)+Var(B)=3+0.25 hours^2=3.25 hours^2

Step-by-step explanation:

Let A the random variable that represent "The arrival time of the plumber ". And we know that the distribution of A is given by:

A\sim Uniform(1 ,7)

And let B the random variable that represent "The time required to fix the broken faucet". And we know the distribution of B, given by:

B\sim Exp(\lambda=\frac{1}{30 min})

Supposing that the two times are independent, find the expected value and the variance of the time at which the plumber completes the project.

So we are interested on the expected value of A+B, like this

E(A +B)

Since the two random variables are assumed independent, then we have this

E(A+B) = E(A)+E(B)

So we can find the individual expected values for each distribution and then we can add it.

For ths uniform distribution the expected value is given by E(X) =\frac{a+b}{2} where X is the random variable, and a,b represent the limits for the distribution. If we apply this for our case we got:

E(A)=\frac{1+7}{2}=4 hours

The expected value for the exponential distirbution is given by :

E(X)= \int_{0}^\infty x \lambda e^{-\lambda x} dx

If we use the substitution y=\lambda x we have this:

E(X)=\frac{1}{\lambda} \int_{0}^\infty y e^{-\lambda y} dy =\frac{1}{\lambda}

Where X represent the random variable and \lambda the parameter. If we apply this formula to our case we got:

E(B) =\frac{1}{\lambda}=\frac{1}{\frac{1}{30}}=30min

We can convert this into hours and we got E(B) =0.5 hours, and then we can find:

E(A+B) = E(A)+E(B)=4+0.5 =4.5 hours

And in order to find the variance for the random variable A+B we can find the individual variances:

Var(A)= \frac{(b-a)^2}{12}=\frac{(7-1)^2}{12}=3 hours^2

Var(B) =\frac{1}{\lambda^2}=\frac{1}{(\frac{1}{30})^2}=900 min^2 x\frac{1hr^2}{3600 min^2}=0.25 hours^2

We have the following property:

Var(X+Y)= Var(X)+Var(Y) +2 Cov(X,Y)

Since we have independnet variable the Cov(A,B)=0, so then:

Var(A+B)= Var(A)+Var(B)=3+0.25 hours^2=3.25 hours^2

3 0
3 years ago
Find the value of x in the figure below
Ksju [112]

Answer:

answers below.

Step-by-step explanation:

50+x+5+180-4x-10=180

225-3x=180

-3x=-45

x=15

m<B=20

m<ACB=110

m<ACD=70

6 0
3 years ago
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