We are given with the variable cost which is:
q = -20s + 400
The selling price is 's'. So, the profit can be represented by:
P = qs - q(12)
Subsituting:
P = (-20s + 400)s - 12 (-20s + 400)
P = -20s^2 + 640s - 4800
To optimize this, we must differentiate the equation and equate it to zero, so:\
dP/ds = -40s + 640 = 0
Solving for s,
s = 16
So, the selling price should be $16 to optimize the yearly profit.
So we will be using
form, in which m = slope and b = y-intercept. Since we know the slope (-8), all we need to do is solve for the y-intercept. We can do this by inserting (-2,2) into the equation and solve for b.

Firstly, do the multiplication: 
Next, subtract 16 on both sides, and your answer will be -14 = b
Using the previous info we have, our equation is y = -8x - 14
First you need to find what 2/3 equals
to do this, take 99 divided by 3
99/3=33
if 1/3 equals 33, two thirds would be 33x2
33x2=66
now, you need to find 1/2 of 66. this can be done 2 different ways
1. 66 divided by 2 - 66/2=33
OR
2. 66 x 1/2 = 33 OR 66 x .5 = 33
The answer is 33 kilograms
Answer:
5
Step-by-step explanation:
The squares with 2, 6, 4, 3 will be all the left, front, right, back sides. The 1 and 5 will flap up/down to be the top and bottom. So 1 and 5 will be opposite from each other.