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pickupchik [31]
2 years ago
10

Solve the equation for x. x2 = 36 The solutions to the equation are and

Mathematics
2 answers:
andrey2020 [161]2 years ago
3 0

x2=36

We move all terms to the left:

x2-(36)=0

We add all the numbers together, and all the variables

x^2-36=0

a = 1; b = 0; c = -36;

Δ = b2-4ac

Δ = 02-4·1·(-36)

Δ = 144

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:

x1=−b−Δ√2ax2=−b+Δ√2a

Δ‾‾√=144‾‾‾‾√=12

x1=−b−Δ√2a=−(0)−122∗1=−122=−6

x2=−b+Δ√2a=−(0)+122∗1=122=6

bekas [8.4K]2 years ago
3 0

9514 1404 393

Answer:

  x = -6 or +6

Step-by-step explanation:

You know from your multiplication tables that 6×6 = 36, so one answer is ...

  x = 6

You also know that the product of two negative numbers is positive, so another answer is ...

  x = -6

__

<em>Check</em>

  x² = 6² = 6×6 = 36

  x² = (-6)² = (-6)×(-6) = 36

_____

<em>Alternate approach</em>

If you like, you can rewrite the equation as ...

  x² -36 = 0

This can be factored to ...

  (x -6)(x +6) = 0

The zero product rule tells you this product will only be zero if one or the other factors is zero.

  x -6 = 0   ⇒   x = 6

  x +6 = 0   ⇒   x = -6

The two solutions are x = ±6.

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Let P (n) be the statement that a postage of n cents can be formed using just 4-cent stamps and 7-cent stamps. The goal is to sh
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Complete Question

Let P (n) be the statement that a postage of n cents can be formed using just 4-cent stamps and 7-cent stamps. The parts of this exercise outline a strong induction proof that P (n) is true for n ≥ 18.

Show statements P (18), P (19), P (20), and P (21) are true, completing the basis step of the proof.

Answer:

P(18) is true

P(19) is true

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a. When n = 18

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