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2 years ago

Solve the equation for x. x2 = 36 The solutions to the equation are and

Mathematics

2 answers:

andrey2020 [161]2 years ago

3 0

x2=36

We move all terms to the left:

x2-(36)=0

We add all the numbers together, and all the variables

x^2-36=0

a = 1; b = 0; c = -36;

Δ = b2-4ac

Δ = 02-4·1·(-36)

Δ = 144

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:

x1=−b−Δ√2ax2=−b+Δ√2a

Δ‾‾√=144‾‾‾‾√=12

x1=−b−Δ√2a=−(0)−122∗1=−122=−6

x2=−b+Δ√2a=−(0)+122∗1=122=6

bekas [8.4K]2 years ago

3 0

9514 1404 393

Answer:

x = -6 or +6

Step-by-step explanation:

You know from your multiplication tables that 6×6 = 36, so one answer is ...

x = 6

You also know that the product of two negative numbers is positive, so another answer is ...

x = -6

Check

x² = 6² = 6×6 = 36

x² = (-6)² = (-6)×(-6) = 36

_____

Alternate approach

If you like, you can rewrite the equation as ...

x² -36 = 0

This can be factored to ...

(x -6)(x +6) = 0

The zero product rule tells you this product will only be zero if one or the other factors is zero.

x -6 = 0 ⇒ x = 6

x +6 = 0 ⇒ x = -6

The two solutions are x = ±6.

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Find the slope of each line and then determine if the lines are parallel, perpendicular or neither. If a value is not an integer

Aleonysh [2.5K]

As given by the question

There are given that the point of two-line

$\begin{gathered} (1,\text{ 7) and (5, 5)} \\ (-1,\text{ -3) and (1, 1)} \end{gathered}$

Now,

From the condition of a parallel and perpendicular line

If the slopes are equal then the lines are parallel

If the slopes are negative reciprocal then the lines are perpendicular

If the slopes are neither of the above are true then lines are neither

Then,

First, find the slope of both of line

So,

For first-line, from the formula of slope

$\begin{gathered} m_1=\frac{y_2-y_1}{x_2-x_1} \\ m_1=\frac{5_{}-7_{}}{5_{}-1_{}} \\ m_1=-\frac{2}{4} \\ m_1=-\frac{1}{2} \end{gathered}$

Now,

For second-line,

$\begin{gathered} m_1=\frac{y_2-y_1}{x_2-x_1} \\ m_1=\frac{1_{}-(-3)_{}}{1-(-1)_{}} \\ m_1=\frac{4}{2} \\ m_1=2 \end{gathered}$

The given result of the slope is negative reciprocal because

$\begin{gathered} -\frac{1}{2}=-(-\frac{2}{1}) \\ -\frac{1}{2}=2 \end{gathered}$

Hence, the slope of line1 is -1/2, and slope of line2 is 2 and the lines are perpendicular.

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1 year ago

Help please................

Zinaida [17]

The answer is yes she incorrectly graphed using the points (-2,4) instead of the point (4,-2). This is the answer because if you solve the equation given you should get y=-3/5x+2/5 so a and e will be wrong and if you plug one of the points in you will give a untrue statement so its not d so you are left with b and c so you plug in the end request and you get a true statement with b equaling -2 if you plug in 4 in for x

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3 years ago

Solve the function below for y when x=12. y=−3x+20

densk [106]

Answer:

y = -16

Step-by-step explanation:

y = -3(12) + 20

y = -36 + 20

y = -16

Hope this helps and pls do mark me brainliest if you can:)

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