When you have 3 choices for each of 6 spins, the number of possible "words" is
3^6 = 729
The number of permutations of 6 things that are 3 groups of 2 is
6!/(2!×2!×2!) = 720/8 = 90
A) The probability of a word containing two of each of the letters is 90/729 = 10/81
The number of permutations of 6 things from two groups of different sizes is
(2 and 4) : 6!/(2!×4!) = 15
(3 and 3) : 6!/(3!×3!) = 20
(4 and 2) : 15
(5 and 1) : 6
(6 and 0) : 1
B) The number of ways there can be at least 2 "a"s and no "b"s is
15 + 20 + 15 + 6 + 1 = 57
The probability of a word containing at least 2 "a"s and no "b"s is 57/729 = 19/243.
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These numbers were verified by listing all possibilities and actually counting the ones that met your requirements.
Answer:
49
Step-by-step explanation:
Answer:
Step-by-step explanation:
y =4/3 x+4
slope intercept form
y = mx+b
the y intercept is 4 (0,4)
and the slope is 4/3 which is change in y over change in x
we go up 4 to the right 3
we can rewrite the slope as -4/-3
so we can go down 4 and to the left 3
this would be point (-3,0)
we have 2 points marked, now draw a line throught them
Answer:
v=12
Step-by-step explanation:
3v-8v+7v=24
3v-v=24
2v=24
v=12
Answer:
Step-by-step explanation: (2,-3) & 9(4,3)
<u>Y2 - Y1</u>
X2 - X1
<u>3 - -3</u>
4 - 2
= <u>6</u>
2
(simplified): = <u>3</u>
1