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LiRa [457]
2 years ago
9

A square field has a perimeter of 48cm find the area of the field​

Mathematics
2 answers:
BabaBlast [244]2 years ago
7 0

Answer:

2,304

Step-by-step explanation:

u multiply one length by it widgth so 48 x 48

faust18 [17]2 years ago
3 0

Answer:

144 m

Step-by-step explanation:

Here , The perimeter of a square=48 m.

Area=?

Since,each side of a square= perimeter/4

=48/4

=12m.

Hence, the area of the square=(side)²

=(12)².

=144 m² Ans.

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PLEASE HELP ME MATH URGENT
slega [8]
S answer is no for the question
7 0
2 years ago
Evaluate the following expressions if ×=2,y=3 and Z=4. a.4×+×-3over ×+10 b.2y-5yover y+5. c.yz-×. d.9+y+zover y+2​
sammy [17]

Answer:

A= 7 11/12 or 7.916 or  95.12

B= 4 1/8 or 4.125 or 33/8

C=  12 4/5 or 12.8 or 64/5

6 0
3 years ago
1) There are 80 grams of salt in a 32% solution. Find the weight of the solution
alukav5142 [94]

Answer:

Weight of the solution = 250 grams

Step-by-step explanation:

1) Consider the weight of solution as x grams.

32 % solution = 80 grams salt

32% of x = 80

(32/100)*x = 80

Solving for x:

x  = (80*100) / 32

x = 250 grams

7 0
3 years ago
On the distant plant, Mathology, a sports area covers 7400 yodels2. How many square deckles would this be if 1 deckle = 75.9 yod
STatiana [176]

Answer:

It would be <u>97.50</u> square deckles.

Step-by-step explanation:

Given:

On the distant plant, Mathology, a sports area covers 7400 yodels².

1 deckle = 75.9 yodels.

Now, to get the square deckles.

As given, 1 deckle = 75.9 yodels.

So, to get the square deckles by using conversion factor:

<em>75.9 yodels = 1 deckle.</em>

7400 yodels² = 7400\div 75.9

                       = 97.50\ deckels ^2.

Therefore, it would be 97.50 square deckles.

8 0
3 years ago
Compare the light gathering power of an 8" primary mirror with a 6" primary mirror. The 8" mirror has how much light gathering p
tankabanditka [31]

Answer:

1.778 times more or 16/9 times more

Step-by-step explanation:

Given:

- Mirror 1: D_1 = 8''

- Mirror 2: D_2 = 6"

Find:

Compare the light gathering power of an 8" primary mirror with a 6" primary mirror. The 8" mirror has how much light gathering power?

Solution:

- The light gathering power of a mirror (LGP) is proportional to the Area of the objects:

                                           LGP ∝ A

- Whereas, Area is proportional to the squared of the diameter i.e an area of a circle:

                                           A ∝ D^2

- Hence,                              LGP ∝ D^2

- Now compare the two diameters given:

                                           LGP_1 ∝ (D_1)^2

                                           LGP ∝ (D_2)^2

- Take a ratio of both:

                           LGP_1/LGP_2 ∝ (D_1)^2 / (D_2)^2

- Plug in the values:

                               LGP_1/LGP_2 ∝ (8)^2 / (6)^2

- Compute:             LGP_1/LGP_2 ∝ 16/9 ≅ 1.778 times more

6 0
3 years ago
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