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2 years ago

I need help on my warm up!! pls thx!

Mathematics

1 answer:

xxMikexx [17]2 years ago

7 0

Step-by-step explanation:

$\tt{30.16 = 17.56 + 5x}$

Swap the sides of the equation :

⤑ $\tt{17.56 + 5x = 30.16}$

We want to remove the 17.56 first.

Since the original equation is 17.56 , we are going to use the opposite operation and subtract 17.56 from both sides :

⤑ $\tt{5x + 17.56 - 17.56 = 30.16 - 17.56}$

Simplify. 17.56 - 17.56 = 0 on the left. 30.16 - 17.36 = 12.6 on the right.

⤑ $\tt{5x = 12.6}$

Then, we need to think about how to remove the coefficient 5. Since the opposite of multiplication is division , I am going to divide both sides by 5.

⤑ $\tt{ \frac{5x}{5} = \frac{12.6}{5}}$

Simplify. 5/5 = 1 on the left and 12.6/5 = 2.52 on the right. So, Our answer is x = 2.52.

$\pink{ \boxed{ \boxed { \tt{Our \: final \: answer : \underline{ \underline{ \bold{ \tt{x = 2.52}}}}}}}}$

Hope I helped ! ♡

Have a wonderful day / night ! ツ

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vivado [14]

Answer:

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Step-by-step explanation:

So, first, you can draw a visual. Refer to the image attached below:

Using this info, you can use trigonometric ratios. Recall that:

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sine = opposite side/ hypotenuse

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You can clearly see that you have an opposite side and a given hypotenuse. This means we'll be using sine.

So:

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2 years ago

What is the average rate of change of the function over the interval x = 0 to x = 6? f(x)=2x−1 3x+5 Enter your answer, as a frac

Tatiana [17]

Answer:

-11

Step-by-step explanation:

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3 years ago

Arvin has $10000 to invest. He invests part in a term deposit paying 5%/year, and the remainder in Canada savings bonds paying 3

Delicious77 [7]

Answer:

$4,562.5

Step-by-step explanation:

The amount Arvin has to invest, P = $10,000

The interest paid on the investment in the term deposit = 5%/year

The interest paid om the investment in Canada savings bonds = 3.4%/year

The amount Arvin earned at the of the year as simple interest, A = $413

Let, x, represent the amount Arvin invested in the term deposit and let, y, represent the amount he invested in Canada savings bonds, we can get the following system of equations

x + y = 10,000...(1)

0.05·x + 0.034·y = 413...(2)

Making y the subject of equation (1) and substituting the value in equation (2), we get;

From equation (1), we get, y = 10,000 - x

Plugging the above value of y in equation (2) gives;

0.05·x + 0.034 × (10,000 - x) = 413

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x = (413 - 340)/(0.05 - 0.034) = 4,562.5

Therefore, the amount Arvin invested in the term deposit at 5%, x = $4,562.5

(y = 10,000 - x

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The amount Arvin invested in Canada savings bonds, y = $5,437.5.)

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