The answer is w + 4 > -12
Answer:

Step-by-step explanation:

Answer:
<h2>2/5</h2>
Step-by-step explanation:
The question is not correctly outlined, here is the correct question
<em>"Suppose that a certain college class contains 35 students. of these, 17 are juniors, 20 are mathematics majors, and 12 are neither. a student is selected at random from the class. (a) what is the probability that the student is both a junior and a mathematics majors?"</em>
Given data
Total students in class= 35 students
Suppose M is the set of juniors and N is the set of mathematics majors. There are 35 students in all, but 12 of them don't belong to either set, so
|M ∪ N|= 35-12= 23
|M∩N|= |M|+N- |MUN|= 17+20-23
=37-23=14
So the probability that a random student is both a junior and social science major is
=P(M∩N)= 14/35
=2/5
Answer:
The graph in the attached figure
Step-by-step explanation:
we have

we know that
To find out the function f(x+1) exchange the variable x for (x+1) in the function f(x)
so



therefore

using a graphing tool
see the attached figure
Answer: 2/5%
Step-by-step explanation: First, convert 0.4 into 4/10. Then, divide the numerator and the denominator by 2. You should get 2/5, which can’t be simplified any more. Voila!