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AlexFokin [52]
3 years ago
12

Hallar el valor de x en 3(x-2)+4=x-5

Mathematics
2 answers:
kolezko [41]3 years ago
8 0

Answer:

exact form 3/2 decimal  form 1.5 mixed number form 1 1/2

Step-by-step explanation:

Leviafan [203]3 years ago
8 0

Answer:

\huge{ \bold{ \boxed{ \tt{x =  -  \frac{3}{2} }}}}

☯\underline{ \underline{ \sf{Question}}} :

  • 3 ( x - 2 ) + 4 = x - 5

☯ \underline{ \underline{ \sf{To \: find}}} :

  • the value of x

\text{Given \: Equation : \: 3(x - 2) + 4 = x - 5}

You must distribute first ! In this equation , you have the distributive property on left hand side of the equation. You must first get rid of the parentheses.

⇢ \text{3  × \: x - 3×  2 + 4 = x - 5}

⇢ \text{3x - 6 + 4 = x - 5}

On the left hand side , you have two numbers : - 6 and 4. Remember that ' The negative and positive numbers are subtracted but posses the sign of the bigger number. '

⇢\sf{3x - 2 = x - 5}

Move x to left hand side and change it's sign.

Similarly , move 2 to right hand side and change it's sign.

⇢\sf{3x - x =  - 5 + 2}

On the left hand side , you have like terms. Combine the like terms : 3x - x = 2x

⇢\sf{2x =  - 5 + 2}

On the right hand side , - 5 + 2 = -3

⇢\sf{2x =  - 3}

Divide both sides by 2

⇢\sf{ \frac{2x}{2}  =  -  \frac{3}{2} }

⇢\boxed{\sf{x =  -  \frac{3}{2} }}

-----------------------------------------------------------------

✏ CHECK :

\text{3(x - 2) + 4 = x - 5}

Substitute \sf{ -  \frac{3}{2}} for x into the original equation. And simplify !

⇾ \sf{3( - \frac{3}{2}  - 2) + 4 =   -  \frac{3}{2}  - 5}

⇾\sf{3( \frac{ - 3 - 2 \times 2}{2} ) + 4 =  \frac{ - 3 - 5 \times 2}{2}}

⇾\sf{3( \frac{ - 3 - 4}{2} ) + 4 =  \frac{ - 3 - 10}{2}}

⇾\sf{3(  \frac{ - 7}{2} ) + 4 =  \frac{ - 13}{2}}

⇾\sf{ \frac{ - 21}{2}  + 4 =  \frac{ - 13}{2}}

⇾\sf{ \frac{ - 21 + 4 \times 2}{2}  =  \frac{ - 13}{2}}

⇾\sf{ \frac{ - 21  +  8}{2}  =  \frac{ - 13}{2}}

⇾\sf{ \frac{ - 13}{2}  =  \frac{ - 13}{2}}

Since both sides are equal , x = \boxed{   - \sf{ \frac{  3}{2} }} is the correct answer.

And we're done !!

Hope I helped!

Have a wonderful day ! ツ

~TheAnimeGirl ♡

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The sales tax charged on a $40 dress was $3.20.what is the sales tax rate charged on the dress?
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3 years ago
∆ ABC is similar to ∆DEF and their areas are respectively 64cm² and 121cm². If EF = 15.4cm then find BC.​
lyudmila [28]

{\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}

★ ∆ ABC is similar to ∆DEF

★ Area of triangle ABC = 64cm²

★ Area of triangle DEF = 121cm²

★ Side EF = 15.4 cm

{\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}

★ Side BC

{\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}

Since, ∆ ABC is similar to ∆DEF

[ Whenever two traingles are similar, the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides. ]

\therefore \tt \boxed{  \tt \dfrac{area( \triangle \: ABC )}{area( \triangle \: DEF)} =  { \bigg(\frac{BC}{EF} \bigg)}^{2}   }

❍ <u>Putting the</u><u> values</u>, [Given by the question]

• Area of triangle ABC = 64cm²

• Area of triangle DEF = 121cm²

• Side EF = 15.4 cm

\implies  \tt  \dfrac{64   \: {cm}^{2} }{12 \:  {cm}^{2} }  =  { \bigg( \dfrac{BC}{15.4 \: cm} \bigg) }^{2}

❍ <u>By solving we get,</u>

\implies  \tt    \sqrt{\dfrac{{64 \: cm}^{2} }{ 121 \: {cm}^{2} }}   =   \bigg( \dfrac{BC}{15.4 \: cm} \bigg)

\implies  \tt    \sqrt{\dfrac{{(8 \: cm)}^{2} }{  {(11 \: cm)}^{2} }}   =   \bigg( \dfrac{BC}{15.4 \: cm} \bigg)

\implies  \tt    \dfrac{8 \: cm}{11 \: cm}    =   \dfrac{BC}{15.4 \: cm}

\implies  \tt    \dfrac{8  \: cm \times 15.4 \: cm}{11 \: cm}    =   BC

\implies  \tt    \dfrac{123.2 }{11 } cm   =   BC

\implies  \tt   \purple{  11.2 \:  cm}   =   BC

<u>Hence, BC = 11.2 cm.</u>

{\large{\textsf{\textbf{\underline{\underline{Note :}}}}}}

★ Figure in attachment.

\rule{280pt}{2pt}

4 0
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