You mean "Simplify 16²÷4³?"
16²=16*16, 16= 4*4
4³=4*4*4
so:
Simplify: <u>16²</u> = <u>16*16</u> = <u>4*4*4*4</u> = <u>4</u> = 4
4³ = 4*4*4 = 4*4*4 1
OR
256 ÷ 64 = 4
Answer: 15 dimes and 13 nickels
Step-by-step explanation:
Answer:
The bottom 3 is separated by weight 7.8896 g and the top 3 is separated by weight 8.1904 g.
Step-by-step explanation:
We are given that
Mean, ![\mu=8.04 g](https://tex.z-dn.net/?f=%5Cmu%3D8.04%20g)
Standard deviation, ![\sigma=0.08g](https://tex.z-dn.net/?f=%5Csigma%3D0.08g)
We have to find the two weights that separate the top 3% and the bottom 3%.
Let x be the weight of machine components
![P(Xx_2)=0.03](https://tex.z-dn.net/?f=P%28X%3Cx_1%29%3D0.03%2C%20P%28X%3Ex_2%29%3D0.03)
![P(X](https://tex.z-dn.net/?f=P%28X%3Cx_1%29%3DP%28Z%3C%5Cfrac%7Bx_1-8.04%7D%7B0.08%7D%29)
=0.03
From z- table we get
![P(Z1.88)=0.03](https://tex.z-dn.net/?f=P%28Z%3C-1.88%29%3D0.03%2C%20P%28Z%3E1.88%29%3D0.03)
Therefore, we get
![\frac{x_1-8.04}{0.08}=-1.88](https://tex.z-dn.net/?f=%5Cfrac%7Bx_1-8.04%7D%7B0.08%7D%3D-1.88)
![x_1-8.04=-1.88\times 0.08](https://tex.z-dn.net/?f=x_1-8.04%3D-1.88%5Ctimes%200.08)
![x_1=-1.88\times 0.08+8.04](https://tex.z-dn.net/?f=x_1%3D-1.88%5Ctimes%200.08%2B8.04)
![x_1=7.8896](https://tex.z-dn.net/?f=x_1%3D7.8896)
![\frac{x_2-8.04}{0.08}=1.88](https://tex.z-dn.net/?f=%5Cfrac%7Bx_2-8.04%7D%7B0.08%7D%3D1.88)
![x_2=1.88\times 0.08+8.04](https://tex.z-dn.net/?f=x_2%3D1.88%5Ctimes%200.08%2B8.04)
![x_2=8.1904](https://tex.z-dn.net/?f=x_2%3D8.1904)
Hence, the bottom 3 is separated by weight 7.8896 g and the top 3 is separated by weight 8.1904 g.
Answer:
yes it is right
Step-by-step explanation: