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nikitadnepr [17]
1 year ago
11

It is estimated that 91% of senior citizens suffer from sleep disorders and 9% suffer from anxiety. Moreover, 6% of seniors suff

erfrom both sleep disorders and anxiety (a) Find the probability that a senior citizen suffers from anxiety, given that he or she has asleep disorder. Round your answer to the nearest hundredth.(b) Given that a senior citizen suffers from anxiety, what is the probability that he or shealso suffers from a sleep disorder? Round your answer to the nearest hundredth.
Mathematics
1 answer:
Fofino [41]1 year ago
8 0

The probability of senior citizens suffer from sleep disorders is

P(A)=0.91

The probability of senior citizens suffer from anxiety is,0.09.

P(B)=0.09

The probability of seniors suffer from both sleep disorders and anxiety is,

P(A\cap B)=0.06

a. The probability that a senior citizen suffers from anxiety, given that he or she has a

sleep disorder.

P(A|B)=\frac{P(A\cap B)}{P(B)}P(A|B)=\frac{0.06}{0.09}P(A|B)=0.67

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So, the definite integral  \int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74

Given that

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We find

\int\limits^1_0 {(4 - 6x^{2} )} \, dx

<h3>Definite integrals </h3>

Definite integrals are integral values that are obtained by integrating a function between two values.

So, Integral \int\limits^1_0 {(4 - 6x^{2} )} \, dx

So, \int\limits^1_0 {(4 - 6x^{2} )} \, dx = \int\limits^1_0 {4} \, dx - \int\limits^1_0 {6x^{2} } \, dx \\=  4[x]^{1}_{0}    - \int\limits^1_0 {6x^{2} } \, dx \\=  4[x]^{1}_{0}    - 6\int\limits^1_0 {x^{2} } \, dx \\= 4[1 - 0]    - 6\int\limits^1_0 {x^{2} } \, dx\\= 4[1]    - 6\int\limits^1_0 {x^{2} } \, dx\\= 4    - 6\int\limits^1_0 {x^{2} } \, dx

Since

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Substituting this into the equation the equation, we have

\int\limits^1_0 {(4 - 6x^{2} )} \, dx = 4 - 6\int\limits^1_0 {x^{2} } \, dx\\= 4 - 6 X 13 \\= 4 - 78\\= -74

So, \int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74

Learn more about definite integrals here:

brainly.com/question/17074932

4 0
2 years ago
Please help!!!!!!!!!
meriva

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n = 8

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Add 2 to each side

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