3 years ago

Which of the following relations is a function?

Mathematics

1 answer:

34kurt3 years ago

5 0

Answer:

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PLEASE HELP ANSWER THIS QUESTION!!!

rewona [7]

Answer:

about 64.03

Step-by-step explanation:

7 0

3 years ago

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How do you solve this

Harman [31]

70+80+(m+10)= 180°
150+m+10=180
160+m=180
m=20°

8 0

3 years ago

ZA and ZB are vertical angles. If m A = (8x – 20)° and m B = (3x – 5)º,

kobusy [5.1K]

Answer:

x=11

Step-by-step explanation:

Vertical angles are congruent, so m∠A = m∠B.

4x+8 = 5x-3

Subtract 5x from both sides.

-1x+8=-3

Subtract 8 from both sides to isolate the variable.

-1x=-11

Divide both sides by -1 to solve for x.

x=11

Plug in 11 for x into m∠A=(4x+8)=(4(11)+8)=(44+8)=52.

4 0

3 years ago

What is the length of BC?

m_a_m_a [10]

It is forty-eight it is easy

5 0

3 years ago

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre

Contact [7]

Answer:

$\dfrac{z-y}{a+b}$

Step-by-step explanation:

Given expression:

$\dfrac{z^2-y^2}{a^2-b^2}\div \dfrac{z+y}{a-b}$

Substitute

$a^2-b^2=(a-b)(a+b)\\ \\z^2-y^2=(z-y)(z+y)$

into the expression:

$\dfrac{(z-y)(z+y)}{(a-b)(a+b)}\div \dfrac{z+y}{a-b}\\ \\ \\=\dfrac{(z-y)(z+y)}{(a-b)(a+b)}\times \dfrac{a-b}{z+y}\\ \\ \\=\dfrac{z-y}{a+b}$

4 0

3 years ago

Read 2 more answers