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VikaD [51]
3 years ago
14

GEOMETRY Identify the segment bisector of (FG) . Then find (FG)

Mathematics
1 answer:
ELEN [110]3 years ago
7 0

Answer:

The segment bisector of FG is HI because it splits it into two equal parts. Since point F to the bisector equals 33 and the bisector to point G is the same, that would also be 33. 33+33=66=FG

Step-by-step explanation:

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Please help asap 26 pts
exis [7]
4 x > − 16 (Possibility 1)
4 x
4 > − 16
4 (Divide both sides by 4)
x > − 4

6 x ≤ − 48 (Possibility 2)
6 x
6 ≤ − 48
6 (Divide both sides by 6)
x ≤ − 8

Answer:
x > − 4 or x ≤ − 8
8 0
3 years ago
Suppose that a wall is constructed from concrete blocks where a block is a normal random variable with mean 11 kg and standard d
Artemon [7]

Answer:

The value for <em>k</em> is about k = 11.093kg.

Step-by-step explanation:

To answer this question, that is, P(x<k) = 0.85, we can use the standardized value for a raw score, or the formula for obtaining z-scores:

\\ z = \frac{x - \mu}{\sigma} [1]

Where

\\ x is the raw score.

\\ \mu is the population mean.

\\ \sigma is the population standard deviation.

In this case, we are asking to find a value x = k, so that 85% of the blocks have weights less than k (kg).

We have also to use the values for the <em>cumulative standard normal distribution</em> with \\ \mu = 0 and \\ \sigma = 1 to find the value of z that corresponds to a probability of 0.85.

First step: find the z that corresponds to the probability of 0.85.

To use the formula [1], as we previously mentioned, we first need to find the value of <em>z</em> that corresponds to a probability of 0.85 using the <em>cumulative standard normal distribution table</em> (available in any Statistics books or on the Internet). Then, for a cumulative probability of 0.85, the corresponding value for z = 1.03 (approximately).

Second step: solve the formula [1] for x.

Solving this formula for x, we have:

\\ z = 1.03

\\ \mu = 11kg

\\ \sigma = 0.09kg

Then (without units):

\\ z = \frac{x - \mu}{\sigma}

\\ 1.03 = \frac{x - 11}{0.09}

\\ 1.03*0.09 = x - 11

\\ (1.03*0.09) + 11 = x

So

\\ x = (1.03*0.09) + 11

\\ x = 0.0927 + 11

\\ x = 11.0927 \approx 11.093 = k

Thus, this value for x = 11.093 equals the value for k (x = k) so that

\\ P(x

Then

\\ P(x or

\\ P(x

We can see the graph below showing this value of k = 11.093kg for which 85% of the blocks have weights less that it (x = k = 11.093kg).  

4 0
3 years ago
1000 cylindrical metal bars of length 120 m and diameter 0.2 m , as shown below, are to be used in constructing a bridge. He bar
Troyanec [42]

Answer:

the number of of litres of paint to the nearest litre for 1000 bars is 1 litre

Step-by-step explanation:

Given that:

1000 cylindrical metal bars have :

a length of 120 m

and a diameter of  0.2 m

The volume of the cylindrical bar can be calculated by the formula:

V= \pi r^2 h

where ;

radius   r=\dfrac{d}{2}

r = \dfrac{0.2}{2}

r = 0.1 m

the length of the cylindrical metal bars is equal to the height of the metal bar = 120 m

Thus the volume can now be calculated as follows:

V= \pi* 0.1^2*120

V = 3.77 m³

So; from the given information.

One litre of paint will cover 4m³

and we want to find how many litres of paint will be used for the 1000 cylindrical bars.

If        1 litre = 4m³

Then  x litre = 3.77 m³

4x = 1 × 3.77

x = \dfrac{1*3.77 }{4}

x = 0.9425 litres

x = 1 litres to the nearest litres.

Thus ; the number of of litres of paint to the nearest litre for 1000 bars is 1 litre

4 0
4 years ago
The average low temperature in a city in August is 49 degrees Fahrenheit and the average high temperatures is 71 degrees fahrenh
Darya [45]

Low August: 9 C or 9.4 C if you need specifics

Avg. August: 22 C or 21.66 if you need specifics


6 0
3 years ago
Read 2 more answers
Identify the angles <br> Hey
lisov135 [29]

Answer:

Complementary, 65°

Step-by-step explanation:

Sum of both angles = 90 so it's complementary angle

given one angle = 25 , other = 90 - 25 = 65

Answer

Complementary, 65°

5 0
3 years ago
Read 2 more answers
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