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3 years ago

Use the distributive property to remove the parentheses.

Mathematics

1 answer:

erik [133]3 years ago

5 0

Divide each term in

Cancel the common factor of

Tap for more steps...

The result can be shown in multiple forms.

Exact Form:

Decimal Form:

1.75

Mixed Number Form:

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3 years ago

What is the answer to 9% of 65?

garri49 [273]

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What is the value of x? Thanks for the help

-BARSIC- [3]

Hello! I can help you! First things first, because they are both the same angles on opposite sides, let's set this up in the form of an equation and solve for "x". It would be set up like this:

2x + 20 = 3x - 30

You see up top that it says 2(x + 10). What you would do is multiply what's in the parenthesis by 2, in order to get 2x + 20. Then put the equal sign and write 3x - 30. Subtract 3x from both sides to get -1x + 20 = -30. Subtract 20 from both sides to get -1x = -50. Divide each side by -1 to isolate the "x". In this case, because you are dividing a negative number by a negative number, your quotient will be positive. -50/-1 is 50. Let's plug in the value as "x" and see if it works. 50 * 2 is 100. 100 + 20 is 120. 50 * 3 is 150. 150 - 30 is 120. 120 = 120. There. x = 50.

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3 years ago

In a large population, 3% of the people are heroin users. A new drug test correctly identifies users 93% of the time and correct

kari74 [83]

Answer:

(a) The probability tree is shown below.

(b) The probability that a person who does not use heroin in this population tests positive is 0.10.

(c) The probability that a randomly chosen person from this population is a heroin user and tests positive is 0.0279.

(d) The probability that a randomly chosen person from this population tests positive is 0.1249.

(e) The probability that a person is heroin user given that he/she was tested positive is 0.2234.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = a person is a heroin user

<em>Y</em> = the test is correct.

Given:

P (X) = 0.03

P (Y|X) = 0.93

P (Y|X') = 0.99

(a)

The probability tree is shown below.

(b)

Compute the probability that a person who does not use heroin in this population tests positive as follows:

The event is denoted as (Y' | X').

Consider the tree diagram.

The value of P (Y' | X') is 0.10.

Thus, the probability that a person who does not use heroin in this population tests positive is 0.10.

(c)

Compute the probability that a randomly chosen person from this population is a heroin user and tests positive as follows:

$P(X\cap Y)=P(Y|X)P(X)=0.93\times0.03=0.0279$

Thus, the probability that a randomly chosen person from this population is a heroin user and tests positive is 0.0279.

(d)

Compute the probability that a randomly chosen person from this population tests positive as follows:

P (Positive) = P (Y|X)P(X) + P (Y'|X')P(X')

$=(0.93\times0.03)+(0.10\times0.97)\\=0.1249$

Thus, the probability that a randomly chosen person from this population tests positive is 0.1249.

(e)

Compute the probability that a person is heroin user given that he/she was tested positive as follows:

$P(X|positive)=\frac{P(Y|X)P(X)}{P(positive)} =\frac{0.93\times0.03}{0.1249}= 0.2234$

Thus, the probability that a person is heroin user given that he/she was tested positive is 0.2234.

6 0

3 years ago