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Alexeev081 [22]
3 years ago
6

Rashaads sister gives him 2 packs of baseball cards per month each pack has 11 cards. She gives him 3 extra packs for his birth

day how many cards does rashaad get in a year.
Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
5 0

Answer:

297 cards in a year

Step-by-step explanation:

There are 12 months in a year, and he gets 2 packs of cards every month.

12*2 = 24 packs of cards a year

He gets 3 extra packs of cards for his birthday.

24 + 3 = 27 packs of cards

There are 11 cards in each pack.

27 X 11 = 297 cards in a year

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21. In the figure given below, AC is parallel to DE. Find the valuesof xy and z and hence find the 2DBE.
algol13

Answer:

X= 50°

Y= 70°

Z= 30°

BDE= 30°

2BDE= 60°

Step-by-step explanation:

(2x -70 )+z+(2x+20)=180...(sum of angle on a straight line)

2x -70 = BDE... alternate angles

Y + (2x-70)+(50+x-20) = 180...(sum of angles in a triangle)

X-20 = z ... alternate and opposite angles

(2x -70 )+z+(2x-+20)=180

2x-70 + x-20 +2x +20= 180

5x -70= 180

5x = 250

X= 50°

X-20 = z

50-20= z

30° = z

2x -70 = BDE

2(50) -70 = BDE

100-70 = BDE

30°= BDE

Y + (2x-70)+(50+x-20)

Y + 100-70 +50 +50 -20 = 180

Y + 200-90=180

Y= 70°

2BDE = 2*30

2BDE= 60°

8 0
3 years ago
I’m in desperate need of help
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3 years ago
A manager recorded how many hours each of 11 cashiers worked in a week. Which interval contains the median number of hours worke
Lana71 [14]

Answer:

Step-by-step explanation:

Hello!

In descriptive statistics, the median is a measurement of center position. It separates the sample in halves. (bottom 50% from upper 50%)

The manager took a sample of 11 cashiers and recorded the worked hours in a week

To identify the median you have to calculate it's position:

The position is calculated as

PosMe= (n+1)/2= (11+1)/2= 6 cashier

This means that the Median of hours worked is a week observed corresponds to the 6th cashier (after ordering the data from lowest to highest)

If you observe the histogram, the x-axis corresponds to worked hours and the y-axis shows the number of workers.

The workers were already arranged from least hours worked to most hours worked.

The first interval corresponds to 0-10 worked hours and two workers recorded these working times.

The second interval corresponds to 10-20 worked hours and three workers recorded these working times.

In the third interval of 20-30 hours, no workers recorded these working times.

The fourth interval corresponds to 30 - 40 worked hours and 5 workers recorded these working times.

The fifth interval corresponds to 40 - 50 worked hours and only one worker recorded these working hours.

The first five workers were recorded in the first two intervals and the sixth worker was recorded in the fourth interval. So the interval that contains the median number of hours worked is "30 - 40 hours"

I hope this helps!

5 0
3 years ago
Prove:ABCD is a parallelogram
labwork [276]

Answer:

Given

Step-by-step explanation:

<A and <D are supplementary

7 0
3 years ago
Find the average value of the function f(x)=−4sin(x) on the interval [π2,3π2] and determine a number c in this interval for whic
Ber [7]

Answer:

Step-by-step explanation:

The average value theorem sets:

if f (x) is continuous in [a, b] and derivable in (a, b) there is a c Є (a, b) such that

\frac{f(b)-f(a)}{b-a}=f'(c) , where

f(a)=f(π/2)=-4*sin(π/2) = -4*1= -4

f(b)=(3π/2)=-4*sin(3π/2) = -4*-1 = 4

\frac{4-(-4)}{(3\pi/2)-(\pi/2)}=f'(c)

\frac{8}{\pi }=f'(c)

f'(x)=-4cos(x) ⇒

f'(c)=-4cos(c)=\frac{8}{\pi }\\c=acos(\frac{-2}{\pi })\\

c≅130

8 0
3 years ago
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