<span>I did the 38 times pi and got 119.3805 then multiplied it by 11
To get 1313.1855
Then divided by 2=
656.59275
And divided by pi
208.9999
Then round up.</span>
Step-by-step explanation:
the max. value is when the smaller set (A) is completely contained in the larger set (B).
then n(A n B) is n(A) = 50.
the set intersection between A and B cannot get bigger than that. or A gets bigger ...
after all, the intersection means it is a set of all elements that exist in BOTH sets.
but then there must be other elements besides A and B in the universal set too, because n(universal set) = 96, and n(A u B) would be only 60.
the min. value could be the empty set or 0. but because n(universal set) = 96, and n(A) + n(B) = 110 and larger than 96, it means that there have to be some shared elements. at least 110 - 96 = 14 elements.
in this case there cannot be other elements in the universal set than A and B. and n(universal set) = n(AuB) = 96.
Jones has 3/4 total fertilizer. He wants to use 1/8 each scoop to use all of the fertilizer.
We need to make these into proportions to understand the amount of each fraction easier. 1/8 = 0.125, and 3/4 = 0.750
To do this the quick way, divide 0.750 by 0.125
0.750/0.125 = 6.
He will have to use the measuring cup 6 times.
Hope this helps!
Answer:
g = 36
Step-by-step explanation:
We have the equation 
+ 7 =19
Subtract 7 from both sides: = 19 - 7 = 12
= 12
Now, multiply by 3 to both sides: 3 × = 3 × 12
g = 36
Answer:
Answer:
safe speed for the larger radius track u= √2 v
Explanation:
The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.
Also given that r_1= smaller radius
r_2= larger radius curve
r_2= 2r_1..............i
let u be the speed of larger radius curve
now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=
r
1
mv
2
=
r
2
mu
2
................ii
form i and ii we can write
v^2= \frac{1}{2} u^2v
2
=
2
1
u
2
⇒u= √2 v
therefore, safe speed for the larger radius track u= √2 v
