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erma4kov [3.2K]
2 years ago
5

A researcher claims that 45% of U.S. adults think that the IRS is not aggressive enough in pursuing people who cheat on their ta

xes. You believe the true percentage is more than 45%. To test this, you take a simple random sample of 500 U.S. adults and find that 245 of them say the IRS is not aggressive enough.
Required:
a. What's the minimum population size required?
c. How many successes were there?
c. Test at 0.01 significance.
Mathematics
2 answers:
marusya05 [52]2 years ago
4 0

I’m just tryna get up my bag yurt

alukav5142 [94]2 years ago
3 0

Answer:

a) Then minimum sample size is  n = 12

b) We got  245 successes  

c)p-value is greater than 0,01 Therefore we accept H₀.

We can´t support our claim

Step-by-step explanation:

a) The minimum population size required to use the approximation of binomial distribution to normal distribution can be obtained from:

n*p > 5      p  = 0,45     0,45 * n  >  5     n > 11  

Then minimum sample size is  n = 12

b)  We got  245 successes  out of  n = 500

x =  245       p  =  245/500    p  = 0,49

q  =  1 - p     q  =  1  - 0,49    q  =  0,51

Test Hypothesis:

Null Hypothesis                        H₀      p  =  0,45

Alternative Hypothesis            Hₐ      p  > 0,45

Alternative Hypothesis indicates that the test is a one tail test to the right

z( s)  =   (  p  -  0,45  )  / √ p*q/n

z( s)  =   (  0,49 - 0,45 ) / √ 0,49*0,51 / 500

z( s)  =  0,04 /  0,0223

z(s)  =  1,793

p- value for  z = 1.79  is from z-table    p-value = 0,0367

Comparing p-value with the significance level  0,01 we see that

p-value is greater than 0,01 Therefore we accept H₀.

We can´t support our claim

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You want to find the equation for a line that passes through the two points:

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So what we need now are the two points you gave that the line passes through. Let's call the first point you gave, (1,17), point #1, so the x and y numbers given will be called x1 and y1. Or, x1=1 and y1=17.

Also, let's call the second point you gave, (2,33), point #2, so the x and y numbers here will be called x2 and y2. Or, x2=2 and y2=33.

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(2,33). When x of the line is 2, y of the line must be 33.

Because you said the line passes through each one of these two points, right?

Now, look at our line's equation so far: y=16x+b. b is what we want, the 16 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (1,17) and (2,33).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!.

You can use either (x,y) point you want..the answer will be the same:

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(2,33). y=mx+b or 33=16 × 2+b, or solving for b: b=33-(16)(2). b=1.

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