Question

Help please jggvnhujff

Answer 1

Answer:

Step-by-step explanation:

8).  $\left \{ {{4x+3y=1} \atop {x+y=2}} \right.$

(2) × [ - 3 ]

4x + 3y = 1 ........ (3)

- 3x - 3y = - 6 .... (4)

(3) + (4)

x = - 5

- 5 + y = 2 ⇒ y = 7

( - 5 , 7 )

9). $\left \{ {{-9x+3y=18} \atop {2x+y=-4}} \right.$

(1) ÷ [- 3]

3x - y = - 6  ......... (3)

2x + y = - 4 ........ (4)

(3) + (4)

5x = - 10 ⇒ x = - 2

2(- 2) + y = - 4 ⇒ y = 0

(- 2, 0)

10). $\left \{ {{x-2y=14} \atop {10x-6y=0}} \right.$

(2) ÷ 10

x - 0.6y = 0 ⇒ x = 0.6y -----> (1)

0.6y - 2y = 14

- 1.4y = 14

y = - 10

x - 2(- 10) = 14 ⇒ x = - 6

(- 6, - 10)

Now is your turn, you can do it!!