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1 answer:
Answer:
Step-by-step explanation:
<u><em>8).</em></u>
<em>(2)</em> × [ - 3 ]
4x + 3y = 1 ........ <em>(3)</em>
- 3x - 3y = - 6 .... <em>(4)</em>
<em>(3)</em> + <em>(4)</em>
x = - 5
- 5 + y = 2 ⇒ y = 7
<em>( - 5 , 7 )</em>
<u><em>9).</em></u>
<em>(1)</em> ÷ [- 3]
3x - y = - 6 ......... <em>(3)</em>
2x + y = - 4 ........ <em>(4)</em>
<em>(3)</em> + <em>(4)</em>
5x = - 10 ⇒ x = - 2
2(- 2) + y = - 4 ⇒ y = 0
<em>(- 2, 0)</em>
<u><em>10).</em></u>
<em>(2)</em> ÷ 10
x - 0.6y = 0 ⇒ x = 0.6y -----> <em>(1)</em>
0.6y - 2y = 14
- 1.4y = 14
y = - 10
x - 2(- 10) = 14 ⇒ x = - 6
<em>(- 6, - 10)</em>
Now is your turn, you can do it!!
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Answer:
see attached
Step-by-step explanation:
The Pythagorean theorem can be used to find the hypotenuse associated with each pair of legs. That tells you ...
c² = a² +b² . . . . . legs a, b; hypotenuse c
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<h3>alternate form of Pythagorean theorem</h3>For the purpose of this problem, it is convenient to consider a slightly different form of the equation.
For legs √a and √b, the hypotenuse √c is given by ...
(√c)² = (√a)² +(√b)²
c = a +b
That is ...
legs √a, √b ⇒ hypotenuse √(a+b)
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<h3>application to this problem</h3>Since the legs are (mostly) given in terms of square roots, the value under the radical for the hypotenuse is simply the sum of those:
legs: √1, √2 ⇒ hypotenuse √(1+2) = √3
legs: √2, √3 ⇒ hypotenuse √(2+3) = √5
legs: √5, √3 ⇒ hypotenuse √(5+3) = √8
legs: √5, √1 ⇒ hypotenuse √(5+1) = √6
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<em>Additional comment</em>
You may not see the leg lengths given as square roots very often. This is a rather unusual set of problems for hypotenuse length.
