From what I think of this question, i think of 9x37 and 8x37 OR 9/37 and 8/37. either way
8x37=296
9x37=333
9/37=0.2432
8/37=0.2162
Answer:
Option 4. x = 0
Step-by-step explanation:
we know that
The rule of the reflection of a point across the y-axis is equal to
(x,y) -----> (-x,y)
The rule for reflecting over the Y axis is to negate the value of the x-coordinate of each point, but leave the y-value the same
The coordinates of triangle PQR are
P(1, 4), Q(3, 6), and R(5, 2)
Applying the rule of the reflection across the y-axis we have
P(1, 4) -----> P'(-1, 4)
Q(3, 6) ----> Q'(-3, 6)
R(5, 2)----> R'(-5, 2)
The reflection line is the y-axis
Remember that the equation of the y-axis is x=0
therefore
The equation of the reflection line is x=0
1/5 of a foot
Simply subtract the height of Pancho’s sandcastle (3/5 of a foot) minus the height of his sister’s sandcastle (2/5 of a foot) to find a difference of 1/5 of a foot, meaning Pancho’s sandcastle was 1/5 of a foot taller than his sister’s sandcastle.
The new cost would be 1661.175 if u want it rounded it would be 1661.18 because you would need to do 1444.5 x .15 and then add that to 1444.5
![\large\begin{array}{l} \textsf{a) }\mathsf{(f\circ g)(x)}\\\\ =\mathsf{f\big[g(x)\big]}\\\\ =\mathsf{\big[g(x)\big]^2-6\cdot g(x)+2}\\\\ =\mathsf{\big[\sqrt{x}\big]^2-6\sqrt{x}+2}\\\\\\ \therefore~~\boxed{\begin{array}{c}\mathsf{(f\circ g)(x)=x-6\sqrt{x}+2} \end{array}}\qquad\checkmark \end{array}](https://tex.z-dn.net/?f=%5Clarge%5Cbegin%7Barray%7D%7Bl%7D%20%5Ctextsf%7Ba%29%20%7D%5Cmathsf%7B%28f%5Ccirc%20g%29%28x%29%7D%5C%5C%5C%5C%20%3D%5Cmathsf%7Bf%5Cbig%5Bg%28x%29%5Cbig%5D%7D%5C%5C%5C%5C%20%3D%5Cmathsf%7B%5Cbig%5Bg%28x%29%5Cbig%5D%5E2-6%5Ccdot%20g%28x%29%2B2%7D%5C%5C%5C%5C%20%3D%5Cmathsf%7B%5Cbig%5B%5Csqrt%7Bx%7D%5Cbig%5D%5E2-6%5Csqrt%7Bx%7D%2B2%7D%5C%5C%5C%5C%5C%5C%20%5Ctherefore~~%5Cboxed%7B%5Cbegin%7Barray%7D%7Bc%7D%5Cmathsf%7B%28f%5Ccirc%20g%29%28x%29%3Dx-6%5Csqrt%7Bx%7D%2B2%7D%20%5Cend%7Barray%7D%7D%5Cqquad%5Ccheckmark%20%5Cend%7Barray%7D)
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![\large\begin{array}{l} \textsf{b) }\mathsf{(g\circ f)(-2)}\\\\ =\mathsf{g\big[f(-2)\big]}\\\\ =\mathsf{\sqrt{f(-2)}}\\\\ =\mathsf{\sqrt{(-2)^2-6\cdot (-2)+2}}\\\\ =\mathsf{\sqrt{4+12+2}}\\\\ =\mathsf{\sqrt{18}}\\\\ =\mathsf{\sqrt{3^2\cdot 2}}\\\\ =\mathsf{3\sqrt{2}}\\\\\\ \therefore~~\boxed{\begin{array}{c}\mathsf{(g\circ f)(-2)=3\sqrt{2}} \end{array}}\qquad\checkmark \end{array}](https://tex.z-dn.net/?f=%5Clarge%5Cbegin%7Barray%7D%7Bl%7D%20%5Ctextsf%7Bb%29%20%7D%5Cmathsf%7B%28g%5Ccirc%20f%29%28-2%29%7D%5C%5C%5C%5C%20%3D%5Cmathsf%7Bg%5Cbig%5Bf%28-2%29%5Cbig%5D%7D%5C%5C%5C%5C%20%3D%5Cmathsf%7B%5Csqrt%7Bf%28-2%29%7D%7D%5C%5C%5C%5C%20%3D%5Cmathsf%7B%5Csqrt%7B%28-2%29%5E2-6%5Ccdot%20%28-2%29%2B2%7D%7D%5C%5C%5C%5C%20%3D%5Cmathsf%7B%5Csqrt%7B4%2B12%2B2%7D%7D%5C%5C%5C%5C%20%3D%5Cmathsf%7B%5Csqrt%7B18%7D%7D%5C%5C%5C%5C%20%3D%5Cmathsf%7B%5Csqrt%7B3%5E2%5Ccdot%202%7D%7D%5C%5C%5C%5C%20%3D%5Cmathsf%7B3%5Csqrt%7B2%7D%7D%5C%5C%5C%5C%5C%5C%20%5Ctherefore~~%5Cboxed%7B%5Cbegin%7Barray%7D%7Bc%7D%5Cmathsf%7B%28g%5Ccirc%20f%29%28-2%29%3D3%5Csqrt%7B2%7D%7D%20%5Cend%7Barray%7D%7D%5Cqquad%5Ccheckmark%20%5Cend%7Barray%7D)
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Tags: <em>composite function composition evaluate algebra</em>
