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-BARSIC- [3]
3 years ago
11

Selma hypothesizes that the mass of a sample of water will not change if it is frozen. She conducts an experiment to test her hy

pothesis. Her experimental steps are as follows:
1. Fill a beaker with 500 mL of water.
2.
3. Place the beaker in the freezer.
4. After the water freezes, place the beaker on the balance and measure its mass.

Which of the following steps is missing from Selma's experiment?

Place the beaker on the balance and measure its mass.
Run the water through a filter to make sure there are no impurities in it.
Set a timer for 2 hours.
Use a thermometer to measure the water's temperature.
Mathematics
2 answers:
egoroff_w [7]3 years ago
4 0
Place a beaker on a balance and measure the mass
Sphinxa [80]3 years ago
4 0

Answer:

place the beaker on the balance and measure its mass.

Step-by-step explanation:

In order to see if the mass of the water changed, Selma first needs to find out what the mass of the liquid water is in order to compare it to the mass of the frozen water.

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Using the figure below, select the pair(s) of supplementary angles. (HINT** they may be more than 1 correct answer)
kondor19780726 [428]

Answer:

B, D

Step-by-step explanation:

Supplementary Angles: Add up to 180 degrees

Angle abe and Angle Ebc add up to 180 degrees

Angle ABD and Angle DBC add up to 180 degrees

3 0
3 years ago
Read 2 more answers
Which decimal number is equal to 4/9?
Ratling [72]
4\9=.444444444
answer=choice D
6 0
3 years ago
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The admission at the movies is $5 for children and $10 for adults. The total amount collected was
sesenic [268]

Answer:

Number of children, x= 400

Number of adults, y = 100

Step-by-step explanation:

Let the number of children be x

Let the number of  adults be y

Given : Total number of people,  x + y = 500  --------(1)

           Total amount collected, 5x + 10y = 3000  ---------(2)

(1) => y = 500 - x

Substitute y in (2) : 5x + 10(500 - x) = 3000

                             5x + 5000 - 10x = 3000

                                -5x = 3000 - 5000

                                 -5x = -2000

                                    x = 400

Substitute x in (1) : 400 + y = 500

                                      y = 500 - 400

                                      y = 100

4 0
3 years ago
If you had 1052 toothpicks and were asked to group them in powers of 6, how many groups of each power of 6 would you have? Put t
sukhopar [10]

1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

The number 1052, written as a base 6 number is 4512

Given: 1052 toothpicks

To do: The objective is to group the toothpicks in powers of 6 and to write the number 1052 as a base 6 number

First we note that, 6^{0}=1,6^{1}=6,6^{2}=36,6^{3}=216,6^{4}=1296

This implies that 6^{4} exceeds 1052 and thus the highest power of 6 that the toothpicks can be grouped into is 3.

Now, 6^{3}=216 and 216\times 5=1080, 216\times 4=864. This implies that 216\times 5 exceeds 1052 and thus there can be at most 4 groups of 6^{3}.

Then,

1052-4\times6^{3}

1052-4\times216

1052-864

188

So, after grouping the toothpicks into 4 groups of third power of 6, there are 188 toothpicks remaining.

Now, 6^{2}=36 and 36\times 5=180, 36\times 6=216. This implies that 36\times 6 exceeds 188 and thus there can be at most 5 groups of 6^{2}.

Then,

188-5\times6^{2}

188-5\times36

188-180

8

So, after grouping the remaining toothpicks into 5 groups of second power of 6, there are 8 toothpicks remaining.

Now, 6^{1}=6 and 6\times 1=6, 6\times 2=12. This implies that 6\times 2 exceeds 8 and thus there can be at most 1 group of 6^{1}.

Then,

8-1\times6^{1}

8-1\times6

8-6

2

So, after grouping the remaining toothpicks into 1 group of first power of 6, there are 2 toothpicks remaining.

Now, 6^{0}=1 and 1\times 2=2. This implies that the remaining toothpicks can be exactly grouped into 2 groups of zeroth power of 6.

This concludes the grouping.

Thus, it was obtained that 1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

Then,

1052=4\times6^{3}+5\times6^{2}+1\times6^{1}+2\times6^{0}

So, the number 1052, written as a base 6 number is 4512.

Learn more about change of base of numbers here:

brainly.com/question/14291917

6 0
2 years ago
1- (-6k + 6) < 3k +1 + 5k
rjkz [21]

Answer:

k>5/14

Step-by-step explanation:

4 0
3 years ago
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