Answer:
a) 0.11
b) 60
Step-by-step explanation:
Total frequency:
12+35+11+23+7+12 = 100
P(3) = 11/100 = 0.11
P(6) = 12/100 = 0.12
Expected no. of sixes:
500 × 0.12 = 60
Y-int . . . x=0 . . . y-3 = 3 (0+1) . . . y-3 = 3 . . y=6. . . . . . . X-int .. y=0 .. 0-3=3 (x+1) .. -3=3x+3 ... -6=3x ...x=-2
Well I believe the answer is A. instead of B,C, or D,
This is because you would not need to multiply right away. The problem addresses that John buys 5 more which means to add and if you needed to multiply right away it would have said twice as much or greater to for an increasive value.
Solution: 2×45+5=f
Answer:
75
Step-by-step explanation:
Let x represent the number of bullfrogs in the population.
We have been given that in a study of the population density of bullfrogs, 25 are captured and marked in the first sampling. Five days later, 30 frogs are captured, 10 of which have marks.
We will use proportion to solve our given problem as:





Therefore, the estimated number of bullfrogs in the population would be 75.