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Luda [366]
3 years ago
9

Find the area of the shaded region helpp!!

Mathematics
1 answer:
sesenic [268]3 years ago
7 0

Answer:

1. 116 m

2. 60 cm

Step-by-step explanation:

1. The total area is 12*10 m, or 120 m. The area of the non-shaded region is 7*2 m, or 14. Subtract 14 from 120 to get 116.

BTW the side 12 looks like it is less than the 10, the question is not lengthed properly, just saying

2. A bit trickier, divide the question into 2 parts, a triangle and rectangle.

The rectangle is 12*4 cm, or 48 cm, the triangle is 12 - 3 - 3 = 6 and 8 - 4 = 4

So we use 6 and 4. The area of a triangle is 1/2b * h, half of the base times the height, the base is 6 cm, and the height is 4 cm, 1/2(6) * 4 = 3*4 = 12 cm

48 + 12 = 60 cm

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Winston earns $140.00 by selling 56 hotdogs at a concession stand at school Using the same rate for the cost of one hotdog, how
Fofino [41]

Answer:

175/2.5=70

Step-by-step explanation:

3 0
3 years ago
If the outlier is removed, which measure will not change?<br><br> mean<br> median<br> mode<br> range
Elena-2011 [213]

Answer:

Out of mean, median, mode, and range, the answer to this question is mode. If an outlier is removed, mode will not change. Hope this helps!

5 0
3 years ago
Please help me solve this: 6 1/3 + k + 3 5/6 + 5 1/2 = 26 1/6
attashe74 [19]
6 1/3 + k + 3 5/6 + 5 1/2 = 26 1/6 
Add your fractions 
6 1/3 + 3 5/6 + 5 1/2 = 15 2/3
now You need to isolate k on one side of the equation by using the subtraction method of equality.
k + 15 2/3 = 26 1/6
k = 10 1/2 

Hope this helps

I had to edit
5 0
3 years ago
Read 2 more answers
The ratio of boys to girls in band class was 3 to 5. If there were 24 boys. How many girls were in band class?
Tamiku [17]

Answer:

40 girls

Step-by-step explanation:

Set up a proportion where x is the number of girls in band class:

\frac{3}{5} = \frac{24}{x}

Cross multiply and solve for x:

3x = 120

x = 40

So, there were 40 girls in band class.

7 0
3 years ago
Read 2 more answers
In the month of June, the temperature in Johannesburg, South Africa, varies over the day in a periodic way that can be modeled a
Art [367]

Answer:

The answer is "\bold{T = - 7.5 \cos \frac{\pi}{12}( t - 4 )+ 10.5}"

Step-by-step explanation:

Given value:

Temp-maximum=18^{\circ}  

Temp. minimum = 3^{\circ}

It is halfway between 10 am and 10 pm to 4 am.  

The sinus and cosine roles could be used throughout the year to predict fluctuations in climate models. Its type of formula that can be used to model such information is:  

T = A \cos B(t-C) + D, where parameters are A, B , C, D, T is the ° C temperature and t is the time (1-24)

A = amplitude = \frac{(T_{max} - T_{min})}{2}\\\\

                       = \frac{(3 - 18)}{2}\\\\= - \frac{15}{2}\\\\ = -7.5

B = \frac{2 \pi}{24}\\\\

   = \frac{\pi}{12}

C = \text{ units translated to the right}= 4

D = y_{min} + amplitude = units \ translated \ up\\\\

D = 7.5 + 3 = 10.5

Its trigonometric function equation that model temperature T hours after midnight in Johannesburg t.

T = - 7.5 \cos \frac{\pi}{12}( t - 4 )+ 10.5

6 0
3 years ago
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