Answer:
The probability that a part was manufactured on machine A is 0.3
Step-by-step explanation:
Consider the provided information.
It is given that Half of a set of parts are manufactured by machine A and half by machine B.
P(A)=0.5
Let d represents the probability that part is defective.
Ten percent of all the parts are defective.
P(d) = 0.10
Six percent of the parts manufactured on machine A are defective.
P(d|A)=0.06
Now we need to find the probability that a part was manufactured on machine A, and given that the part is defective
:



Hence, the probability that a part was manufactured on machine A is 0.3
900=(1/2)*b*10*15
1800=150b
b=12
I hope you can figure out FC with this info.
Answer:
52
Step-by-step explanation:
add add add add add add adddaddd addda
Answer:
Follow the steps I did in the explanation.
Step-by-step explanation:
It says to evaluate the equation :-
3.2 = 4/5(b - 5)
3.2 = (4/5 × b) + (4/5 × -5)
3.2 = 4/5b - 4
3.2 + 4 = 4/5b
5/4 × 7.2 = b
9 = b
Hope this helps, thank you :) !!