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timurjin [86]
3 years ago
7

Greg ran 3 times as far as jed.rj ran 0.1times as far as Greg. If jed ran25 yards, how far did Greg and rj run

Mathematics
1 answer:
azamat3 years ago
3 0
Greg's distance is 3 times than Jed. so, 25 yards * 3 = 75 yards. And RJ ran only 0.1 times than Greg (75 yards). So, it should be 7.5 yards
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juin [17]
Alexandera=a
imani=i

a is 8 more than i or
a=8+i

the sum of the 2 numbers is 50 or
a+i=50

a=8+i
so subsitute 8+i for a in a+i=50
8+i+i=50
8+2i=50
subtract 8 from both sides
2i=42
divide both sides by 2
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subsiutte into a=8+i

a=8+21
a=29



a=29
i=21
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I believe its approx. 2.365 because if you do 

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3 years ago
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s344n2d4d5 [400]

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It helps to have some idea what the log function is.

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3 years ago
Find the width of a rectangle 25 feet and the perimeter is 80​
lukranit [14]

\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}

  • Given - <u>a </u><u>rectangle </u><u>with </u><u>length</u><u> </u><u>2</u><u>5</u><u> </u><u>feet </u><u>and </u><u>perimeter </u><u>8</u><u>0</u><u> </u><u>feet</u>

  • To calculate - <u>width </u><u>of </u><u>the </u><u>rectangle</u>

We know that ,

\bold{Perimeter \: of \: rectangle = 2(l + b)} \\

where <u>b </u><u>=</u><u> </u><u>width </u><u>/</u><u> </u><u>breadth</u> of rectangle

‎ ‎ ‎

<u>substituting</u><u> </u><u>the </u><u>values </u><u>in </u><u>the </u><u>formula </u><u>stated </u><u>above </u><u>,</u>

\bold{80  = 2(25 + b)} \\  \\\bold{ \implies \: 25 + b = \cancel \frac{80}{2} } \\  \\ \bold{\implies \: 25 + b = 40 }\\  \\ \bold{\implies \: b = 40 - 25 }\\  \\\bold{ \implies \: b = 15 \: feet}

hope helpful ~

3 0
2 years ago
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