Help me please!!!!!!!!!!!!

Natalia solved the problem 74.4/12=6.2. complete the model with partial products check Natalia's work using multiplication

tia_tia [17]

Answer:

Natalia's work is wrong.

Step-by-step explanation:

Natalia divided a decimal number by an entire number. Since division is a operation derived from multiplication, the best approach to check if work was good is multiplying the given result by denomination, that is:

1) $x = 6.2\times 12$ Given.

2) $x = \left(6+0.2\right)\times 12$ Definition of addition.

3) $x = 6\times 12 + 0.2\times 12$ Distributive property.

4) $x = 72 + \frac{2}{10}\times 12$ Definitions of multiplication and decimal number.

5) $x = 72 +[2\cdot (10)^{-1}]\cdot 12$ Definition of division/Associative property.

6) $x = 72 + [2\cdot 12]\cdot (10)^{-1}$ Associative property.

7) $x = 72 + 24\cdot 10^{-1}$ Definition of multiplication.

8) $x = 72 + \frac{24}{10}$ Definition of divsion.

9) $x = 72 + 2.4$ Defintion of decimal number.

10) $x = 74.4$ Definition of addition/Result

Natalia's work is wrong.

5 0

3 years ago

Owning a small and successful business isn't easy! There is a monthly cost of shipping supplies and

andriy [413]

Answer:

$C(x)=24,000+19,200x$

Step-by-step explanation:

<u>Mathematical Modeling</u>

To model a real-life situation, a mathematical model can be constructed in such a way it accurately represents the variables measured in the system.

This problem requires to build a model for the yearly cost of a small and successful business.

The first data is the fixed monthly cost or the money the owner must pay regardless of the number of employees he hires. This cost includes shipping supplies and products for $2,000. To operate for a full year, the fixed cost is 12*$2,000=$24,000.

The other component of the cost function is the variable cost of x employees. Given each employee costs $1,600 each month, having x employees cost 1,600x each month. For a full year, the variable cost will be

12*1,600x=19,200x.

We finally form the total cost function:

$\boxed{C(x)=24,000+19,200x}$

7 0

3 years ago

PLEASE PLEASE PLEASE HELP I NEED HELP WITH THIS :((<br> i will give brainliest:)

bezimeni [28]

-3+8=5

2-6=-4

-3+-1=-4

4 0

3 years ago

Your neighbor has a bag with 5 oranges and 7 apples in it. You will be receiving two pieces of fruit from your neighbor. What is

Snezhnost [94]

Answer:

31.82% probability that you will receive 2 apples.

Step-by-step explanation:

The fruits are removed from the bag, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

5 + 7 = 12 total fruits, which means that $N = 12$

7 apples, which means that $k = 7$

You receive 2 fruits, which means that $n = 2$

What is the probability, in percent, that you will receive 2 apples, assuming she removes them from the bag in random order?

This is, as a proportion, P(X = 2). So

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 2) = h(2,12,2,7) = \frac{C_{7,2}*C_{5,0}}{C_{12,2}} = 0.3182$

0.3182*100% = 31.82%

31.82% probability that you will receive 2 apples.

4 0

3 years ago

Sviatoslav solved the quadratic equation x^2-x-1=0 by completing the square. In the process, he came up with the equivalent equa

zimovet [89]

Answer:

$x=\frac{1+\sqrt5}{2}$ and $x=\frac{1-\sqrt5}{2}$

and b= $\frac{5}{4}$

Step-by-step explanation:

We are given that a quadratic equation

$x^2-x-1=0$

We have to solve the equation by completing square and find the value of b.

$(x)^2-2\times x\times \frac{1}{2}+(\frac{1}{2})^2-(\frac{1}{2})^2-1=0$

$(x-\frac{1}{2})^2-\frac{1}{4}-1=0$

$(x-\frac{1}{2})^2-\frac{1-4}{4}=0$

$(x-\frac{1}{2})-\frac{5}{4}=0$

$(x-\frac{1}{2})^2-(\frac{\sqrt5}{2})^2=0$

$(x-\frac{1}{2})^2=(\frac{\sqrt5}{2})^2$

$x-\frac{1}{2}=\frac{\sqrt5}{2}$ and $x-\frac{1}{2}=-\frac{\sqrt5}{2}$

$x=\frac{\sqrt5}{2}+\frac{1}{2}=\frac{1+\sqrt5}{2}$

And $x=\frac{1}{2}-\frac{\sqrt5}{2}=\frac{1-\sqrt5}{2}$

Therefore, $x=\frac{1+\sqrt5}{2}$ and $x=\frac{1-\sqrt5}{2}$

and b= $\frac{5}{4}$

6 0

3 years ago